如何提取 byte[]
从 String
用正确的格式编码?
这就是我的情况。
byte[] bytes = // some byte[] derived from custom code
String bytesString = // some string derived from the bytes above with custom code
byte[] newBytes = // TODO: transform bytesString back into bytes above
System.out.println(Arrays.toString(bytes));
// [74, -61, 58, 97, 127, -8, -5, -123, 70, 51, 65, 109, -20, -43, 117, 83]
System.out.println(bytesString);
// JÃ:aøû…F3AmìÕuS
System.out.println(Arrays.toString(bytesString.getBytes())); // similar but not identical
// [74, -61, -125, 58, 97, 127, -61, -72, -61, -69, -62, -123, 70, 51, 65, 109, -61, -84, -61, -107, 117, 83]
我想把... bytesString
上回确切的 byte[]
. 这是我得到的最接近的结果。
byte[] newBytes = bytesString.getBytes("UTF-16LE");
System.out.println(newBytes); // identical if we remove the 0s
// [74, 0, -61, 0, 58, 0, 97, 0, 127, 0, -8, 0, -5, 0, -123, 0, 70, 0, 51, 0, 65, 0, 109, 0, -20, 0, -43, 0, 117, 0, 83, 0]
当然,我不想只从上面的数组中去掉0号。我缺少了什么?
快速演示处理字节数组和String时如何正确使用字符集。
byte[] arr = {74, -61, 58, 97, 127, -8, -5, -123, 70, 51, 65, 109, -20, -43, 117, 83};
String bytesString = new String(arr, "ISO-8859-1"); // or "UTF-16LE"
byte[] bbb = bytesString.getBytes("ISO-8859-1"); // or "UTF-16LE"
System.out.println("string : '" + bytesString + "'");
System.out.println("input array: " + Arrays.toString(arr));
System.out.println("bytesString: " + Arrays.toString(bbb));
打印相等的字节数组。
string : '썊愺藻㍆流헬卵'
input array: [74, -61, 58, 97, 127, -8, -5, -123, 70, 51, 65, 109, -20, -43, 117, 83]
bytesString: [74, -61, 58, 97, 127, -8, -5, -123, 70, 51, 65, 109, -20, -43, 117, 83]
打印相同的结果,如果 "UTF-16LE"
在创建字符串和从字符串中获取字节时,都会提供charset。