将 Soap XML 响应转换为对象

问题描述 投票:0回答:5

我是 SOAP API 的新手

我有来自 API 的肥皂响应

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
<LoginResponse xmlns="http://test.org/ADMail_Service">
<LoginResult>
<ErrorMessage>Successful login</ErrorMessage>
<Status>true</Status>
</LoginResult>
</LoginResponse>
</soapenv:Body>
</soapenv:Envelope>

我正在尝试将其转换为一个对象。

通过在线阅读文章,我尝试使用 JAXB 来执行此操作,但我的对象是空的。

这是读取响应的代码。我将响应写入 xml 文件以进行测试:

try {
    XMLInputFactory xif = XMLInputFactory.newFactory();
    XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
    xsr.nextTag(); // Advance to Envelope tag

    xsr.nextTag(); // Advance to Body tag
    xsr.nextTag();
    xsr.nextTag();


    JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
    Unmarshaller unmarshaller = jc.createUnmarshaller();
    JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);

    System.out.println(je.getName());
    System.out.println(je.getValue());
} catch (XMLStreamException e) {
    e.printStackTrace();
} catch (JAXBException e) {
    e.printStackTrace();
} catch (FileNotFoundException e) {
    e.printStackTrace();
}

LoginResult
班:

public class LoginResult {
    private String errorMessage;
    private String status;

    public String getErrorMessage() {
        return errorMessage;
    }

    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }
}

提前致谢!

java xml soap jaxb
5个回答
8
投票

您可以使用此代码检索 POJO,还可以将 @XmlRootElement 作为标头添加到 POJO。

(我没有测试下面的代码)

XMLInputFactory xif = XMLInputFactory.newFactory();
        XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
        xsr.nextTag(); // Advance to Envelope tag

        xsr.nextTag(); // Advance to Body tag
        xsr.nextTag();
        xsr.nextTag();

        Transformer transformer = TransformerFactory.newInstance().newTransformer();
        StringWriter stringWriter = new StringWriter();
        transformer.transform(new StAXSource(xsr), new StreamResult(stringWriter));
        StringReader sr = new StringReader(stringWriter.toString());
        JAXBContext jaxbContext = JAXBContext.newInstance(LoginResult.class);
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        LoginResult loginResult = (LoginResult) unmarshaller.unmarshal(sr);

编辑:

我为你找到了解决方案:

    @XmlRootElement(name = "LoginResult", namespace = "http://test.org/ADMail_Service")
@XmlAccessorType(XmlAccessType.FIELD)
public class LoginResult {
    @XmlElement(name = "ErrorMessage", namespace = "http://test.org/ADMail_Service")
    private String errorMessage;
    @XmlElement(name = "Status", namespace = "http://test.org/ADMail_Service")
    private String status;

    public String getErrorMessage() {
        return errorMessage;
    }

    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }
}


public static void main(String[] args) {
        try {
            XMLInputFactory xif = XMLInputFactory.newFactory();
            XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
            xsr.nextTag(); // Advance to Envelope tag

            xsr.nextTag(); // Advance to Body tag
            xsr.nextTag();
            xsr.nextTag();


            JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
            Unmarshaller unmarshaller = jc.createUnmarshaller();
            JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);

            System.out.println(je.getName());
            System.out.println(je.getValue());
            System.out.println(je.getValue().getErrorMessage());
        } catch (XMLStreamException e) {
            e.printStackTrace();
        } catch (JAXBException e) {
            e.printStackTrace();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }

    }

5
投票

IMO,您应该考虑使用工具来处理 SOAP 消息,而不是自己处理

示例:


编辑

关于您的评论有一些话要说,所以我将我的答案放在这里。

首先,

我与 API 无关,我所做的只是发出 POST 请求...

您与 API 没有任何关系,但您向 API 发出 POST 请求。 我觉得这是一个比喻吧?...

并且没有 wsdl....

通过这个小技巧,您几乎总能获得 SOAP Web 服务的 WSDL。只需在 SOAP Web 服务 URL 末尾添加

?wsdl

示例:

这是网络上 SOAP Web 服务的 URL(真实的):http://www.webservicex.com/stockquote.asmx

您可以像这样获取它的 WSDL :http://www.webservicex.com/stockquote.asmx?wsdl

所以唯一的选择是解析响应

IMO,软件开发中的问题几乎总是有不止一种解决方案。


0
投票

有时,我发现了这段用于将soapxml对象解析为java对象的代码。

private <T> T getJavaObjectFromSoapXml(String responseFilePath, Class<T> clazz) {
try {
  XMLInputFactory xif = XMLInputFactory.newFactory();
  StreamSource xml = new StreamSource(getClass().getResourceAsStream(responseFilePath));
  XMLStreamReader xsr = xif.createXMLStreamReader(xml);
  xsr.nextTag();
  while (!xsr.getLocalName().equalsIgnoreCase(clazz.getSimpleName())) {
    xsr.nextTag();
  }

  JAXBContext jc = JAXBContext.newInstance(clazz);
  Unmarshaller unmarshaller = jc.createUnmarshaller();

  JAXBElement<T> je = unmarshaller.unmarshal(xsr, clazz);
  return je.getValue();
} catch (Exception e) {
  e.printStackTrace();
  return null;
}
}

0
投票
public  <T> T getJavaObjectFromSoapXml(String response, Class<T> clazz) {
        try {
            XMLInputFactory xif = XMLInputFactory.newFactory();
            StreamSource xml = new StreamSource(response);
            XMLStreamReader xsr = xif.createXMLStreamReader(new StringReader(response));
            xsr.nextTag();
            while (!xsr.getLocalName().equalsIgnoreCase(clazz.getSimpleName())) {
                log.info("TAG :{}",xsr.nextTag());
            }

            Transformer transformer = TransformerFactory.newInstance().newTransformer();
            StringWriter stringWriter = new StringWriter();
            transformer.transform(new StAXSource(xsr), new StreamResult(stringWriter));
            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();

            Document document = builder.parse(new InputSource(new StringReader(stringWriter.toString())));
            JAXBContext jaxbContext = JAXBContext.newInstance(clazz);
            Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
            T t = (T) unmarshaller.unmarshal(document);
            return t;
        } catch (Exception e) {
            e.printStackTrace();
            return null;
        }
    }

0
投票
public static <T> T unmarshallSoapResponse(final byte[] soapMessage,
            Class<T> clazz) throws IOException, SOAPException, JAXBException {
        SOAPMessage message = MessageFactory.newInstance().createMessage(null, new ByteArrayInputStream(soapMessage));
        Unmarshaller unmarshaller = JAXBContext.newInstance(clazz).createUnmarshaller();
        return (T) unmarshaller.unmarshal(message.getSOAPBody().extractContentAsDocument());
    }
© www.soinside.com 2019 - 2024. All rights reserved.