使用PHP解析JSON API

Question

我正在使用BooksRun API，并且无法使用PHP foreach显示从API返回的任何数据。我的代码如下。预先感谢！

BooksRun API Reference

<?php
//PARAMETERS
$url = 'https://booksrun.com/api/v3/price/buy/0134093410?key=0t8rfbno7qc4lmaav9yz';

$headers = array(
"Content-type: application/json;charset=\"utf-8\"",
"Accept: text/xml",
"Cache-Control: no-cache",
"Pragma: no-cache",
"SOAPAction: \"run\""
 ); 

$cURL = curl_init();

curl_setopt($cURL, CURLOPT_URL, $url);
curl_setopt($cURL, CURLOPT_HTTPGET, true);
curl_setopt($cURL, CURLOPT_HTTPHEADER, $headers);
curl_setopt($cURL, CURLOPT_RETURNTRANSFER, 1);

$result = curl_exec($cURL);
curl_close($cURL);
//Json Data decoded on PHP object
$obj_data = json_decode($result);

echo '<div>' . 'start : '.$obj_data->result->status . '</div>';
//echo '<div>' . 'date: '.$obj_data->result->offers->booksrun->new->price . '</div>';
//echo '<div>' . 'date: '.$obj_data->result->marketplace->used->price . '</div>';

foreach ($obj_data->result as $book) {
//fetch object data

echo '<div>' . 'seller: '.$book->offers->booksrun->rent->price . '</div>';
echo '<div>' . 'date: '.$book->marketplace->used->price . '</div>';

  }
?>

Answer 1

只需进行以下更改：

echo '<div>' . 'seller: '.$obj_data->result->offers->booksrun->rent->{"35"}->price . '</div>';
echo '<div>' . 'date: '.$obj_data->result->offers->marketplace[0]->used->price . '</div>';

$obj_data->result->offers->marketplace是一个数组，因此可以在其上循环。

不需要遍历结果对象，因为它只包含一项。

Answer 2

如果添加，可能会有用

curl_setopt($cURL, CURLOPT_SSL_VERIFYPEER, false); 

之后

curl_setopt($cURL, CURLOPT_RETURNTRANSFER, 1);

Answer 3

我认为您需要更改代码，因为json中有一个数组也许您可以更改为此代码]

<?php
//PARAMETERS
$url = 'https://booksrun.com/api/v3/price/buy/0134093410?key=0t8rfbno7qc4lmaav9yz';

$headers = array(
"Content-type: application/json;charset=\"utf-8\"",
"Accept: text/xml",
"Cache-Control: no-cache",
"Pragma: no-cache",
"SOAPAction: \"run\""
 ); 

$cURL = curl_init();

curl_setopt($cURL, CURLOPT_URL, $url);
curl_setopt($cURL, CURLOPT_HTTPGET, true);
curl_setopt($cURL, CURLOPT_HTTPHEADER, $headers);
curl_setopt($cURL, CURLOPT_RETURNTRANSFER, 1);

$result = curl_exec($cURL);
curl_close($cURL);
//Json Data decoded on PHP object
$obj_data = json_decode($result);
echo '<div>' . 'start : '.$obj_data->result->status . '</div>';
//echo '<div>' . 'date: '.$obj_data->result->offers->booksrun->new->price . '</div>';
//echo '<div>' . 'date: '.$obj_data->result->marketplace->used->price . '</div>';

//fetch object data
foreach ($obj_data->result->offers->booksrun->rent as $rent) {
    echo '<div>' . 'seller: '.$rent->price . '</div>';
}
foreach ($obj_data->result->offers->marketplace as $marketplace) {
    echo '<div>' . 'date: '.$marketplace->used->price. '</div>';
}
?>

代码中的问题是您想打开一个对象，但实际上它是一个数组