汇总字典的python列表

问题描述 投票:-4回答:1

给出以下python字典列表:

product_issues = [

{'product':'battery',
'High': 0,
'Med':1
'Low':0
 '},

{'product':'battery',
'High': 1,
'Med':0
'Low':0
 '},

{'product':'battery',
'High': 1,
'Med':0
'Low':0
 '},


{'product':'tape',
'High': 1,
'Med':0
'Low':0
 '},

{'product':'tape',
'High': 1,
'Med':0
'Low':0
 '},

]

为每种产品提供以下H / M / L摘要:

product_issues_summary = [

{'product':'battery',
'High': 2,
'Med':1
'Low':0
 '},

{'product':'tape',
'High': 2,
'Med':0
'Low':0
 '},
]

感谢任何反馈。

python python-3.x list dictionary summarize
1个回答
0
投票

这里您可以尝试。它使用collections.defaultdictcollections.Counter计算每个HighMedLowproduct,然后在最后合并结果。

from collections import defaultdict, Counter

product_issues = [
    {"product": "battery", "High": 0, "Med": 1, "Low": 0},
    {"product": "battery", "High": 1, "Med": 0, "Low": 0},
    {"product": "battery", "High": 1, "Med": 0, "Low": 0},
    {"product": "tape", "High": 1, "Med": 0, "Low": 0},
    {"product": "tape", "High": 1, "Med": 0, "Low": 0},
]

d = defaultdict(Counter)
for product in product_issues:
    levels = {k: v for k, v in product.items() if k != "product"}
    d[product["product"]].update(levels)

print([{**{"product": k}, **v} for k, v in d.items()])

汇总结果:

[{'product': 'battery', 'High': 2, 'Med': 1, 'Low': 0}, {'product': 'tape', 'High': 2, 'Med': 0, 'Low': 0}]
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