我使用Microsoft SQL Server(2016)我有一个称为故障转移的列该列看起来像
1. $D$Failov:12345:54362:28564
2. $D$Failov:12345:
3. $D$Failov:86905:45634
我想要这个数字,所以我用:
select substring(failover,10,5)
from dbo.f009
where failover like '$D$Failov:%'
它工作正常,但是如果我要一个称为Account的第二列,它崩溃了,结果不一而足……
Select account,
(Select substring(failover,10,5) AS "1.Result"
from dbo.f009
where Failover like '$D$Failov:%')
from f009
where Failover like '$D$Failov:%'
如何解决?
substring(failover,16,5), substring(failover,22,5)
等来完成此操作,但不会重复我自己。似乎您想要的东西可以通过一个简单的查询来实现:
Select account, substring(failover,10,5) AS "1.Result"
from dbo.f009
where Failover like '$D$Failov:%'