Django上的用户关注者模型。不能在指定中间模型的ManyToManyField上使用add()。使用accounts.Contact的经理

问题描述 投票:2回答:2

我是Django的新手,请原谅代码或逻辑中的任何愚蠢错误,

简介:我正在尝试在Django中创建用户关注者模型。用户可以关注和取消关注网站上的其他用户

错误:我已经为我的关注/取消关注做了models我也做了views我收到此错误

AttributeError at /accounts/admin/follow/
Cannot use add() on a ManyToManyField which specifies an intermediary model. Use accounts.Contact's Manager instead. 

obj.followers.add(user)在回溯中突出显示为错误的起源

以下是我的models.py

from django.contrib.auth.models import User
class Profile(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    city = models.CharField(max_length=100)
    country = models.CharField(max_length=100)
    def get_absolute_url(self):
        return reverse('accounts:profile', kwargs={'username': self.user.username})

class Contact(models.Model):
    user_from = models.ForeignKey(User, related_name='suppporter')
    user_to = models.ForeignKey(User, related_name='leader')

    def __str__(self):
        return '{} follows {}'.format(self.user_from, self.user_to)


User.add_to_class('following',
                  models.ManyToManyField('self', through=Contact, related_name='followers', symmetrical=False))

我认为models.py可能会很好。我相信的错误在于我的观点。下面是我的view.py

class FollowToggle(LoginRequiredMixin, RedirectView):

    def get_redirect_url(self, *args, **kwargs):
        username = self.kwargs.get('username')
        print(username + " This is the user who will be followed") # This prints correct
        profile = get_object_or_404(Profile, user__username=username)
        print(profile) # This prints correct
        obj = get_object_or_404(User, username=username)
        print(obj) # This prints correct
        url_ = profile.get_absolute_url()
        print(url_) # This prints correct
        user = self.request.user
        print(user) # This prints correct
        if user.is_authenticated():
            if user in obj.followers.all(): # I know this is the source of the error.
                obj.followers.remove(user)
            else:
                obj.followers.add(user)
        return url_

以下是Urls.py以防万一

url(r'^(?P<username>[-\w]+)/follow/$', views.FollowToggle.as_view(), name='follow'),
python django django-models django-views django-users
2个回答
2
投票

您不能将addremove方法用于通过第三个模型定义的多种关系。来自docs

与普通的多对多字段不同,您不能使用add(),create()或set()来创建关系

相反,你应该使用Contact经理:

if user.is_authenticated():
    if user in obj.followers.all(): # I know this is the source of the error.
        Contact.objects.filter(user_to=obj, user_from=user).delete()
    else:
        Contact.objects.create(user_to=obj, user_from=user)

1
投票

在Django 2.2中你可以使用addremoveset方法(Docs

您也可以使用add(),create()或set()来创建关系,只要为任何必填字段指定through_defaults即可

© www.soinside.com 2019 - 2024. All rights reserved.