有什么方法可以在 presto 中有效地将行扩展到列吗?
我尝试分别使用“where team = 1”和“where team = 2”过滤原始数据集,首先相应地获取数据集1和数据集2,然后在invenue_level上加入两个数据集。然而,当收入水平有太多不同的值时,会很不方便。有什么有效的方法可以得到我想要的结果吗?
Prestodb 提供了
map_agg
功能,可以帮助您将长数据转换为您正在寻找的宽格式。不幸的是,似乎没有一种方法可以动态创建列名称,但这种方法应该比加入每个团队更有效(并且更少打字:))。
WITH raw_data AS (
SELECT 1 AS team, 'a' AS income_level, 1 AS time, 11 AS ord
UNION
SELECT 1 AS team, 'b' AS income_level, 2 AS time, 12 AS ord
UNION
SELECT 1 AS team, 'c' AS income_level, 3 AS time, 13 AS ord
UNION
SELECT 2 AS team, 'a' AS income_level, 4 AS time, 14 AS ord
UNION
SELECT 2 AS team, 'b' AS income_level, 5 AS time, 15 AS ord
UNION
SELECT 2 AS team, 'c' AS income_level, 6 AS time, 16 AS ord
UNION
SELECT 3 AS team, 'a' AS income_level, 7 AS time, 17 AS ord
UNION
SELECT 3 AS team, 'b' AS income_level, 8 AS time, 18 AS ord
UNION
SELECT 3 AS team, 'c' AS income_level, 9 AS time, 19 AS ord
)
SELECT
income_level,
team_time[1] AS time_1,
team_ord[1] AS ord_1,
team_time[2] AS time_2,
team_ord[2] AS ord_2,
team_time[3] AS time_3,
team_ord[3] AS ord_3
FROM (
SELECT
income_level,
map_agg(team, time) AS team_time,
map_agg(team, ord) AS team_ord
FROM raw_data
GROUP BY income_level
);
输出:
| income_level | time_1 | ord_1 | time_2 | ord_2 | time_3 | ord_3 |
|--------------|--------|-------|--------|-------|--------|-------|
| a | 1 | 11 | 4 | 14 | 7 | 17 |
| b | 2 | 12 | 5 | 15 | 8 | 18 |
| c | 3 | 13 | 6 | 16 | 9 | 19 |
此网站提供了另一个如何完成此操作的示例。