我有一个包含列表值的词典:
{
'List1' : ['Value1', 'Value2', 'Value3'],
'List2' : ['Value1', 'Value2', 'Value3'],
'List3' : ['Value1', 'Value2', 'Value3'],
}
我想迭代每个列表的值来查找正则表达式,然后创建一个包含这些正则表达式的字典。也就是说,对于我的初始字典的每个列表。我的列表上的每次迭代(前一个例子中的3个)都会创建1行(总共3行),因此我会运行一个代码来创建一个全面的唯一行。
不确定是否清楚,但它看起来应该类似于:
for list in dictionary:
for value in list:
column_list_A = []
if re.search(regex, value):
column_list_A.append(regex, value).group(1)
column_list_B = []
if re.search(regex, value):
column_list_B.append(regex, value).group(1)
New_Dictionary = {"column_list_A" : column_list_A, "column_list_B" : column_list_B}
Df = pd.DataFrame.from_dict(New_Dictionary)
for column in Df:
#Code that puts the values of the 3 rows into 1 row
输出应如下所示:
| Column_list_A | Column_list_B
----------------------------------------------------
List1 | match object | match object
----------------------------------------------------
List2 | match object | match object
----------------------------------------------------
List3 | match object | match object
我的问题是:
1)如何实现嵌套的for循环?我尝试过像iteritems()这样的东西,但它没有给出令人满意的结果。对于每个循环,X和Y究竟应该在“for X in Y”中?
2)压痕是否正确?
如果你希望你的最终输出是一个数据帧,我建议你使用可以自己很好地处理循环和正则表达式的熊猫函数,而不需要for循环。这是一个例子:
import pandas as pd
# read dict in the right orientation
df = pd.DataFrame.from_dict(dictionary, orient="index")
''' # your df will look like this:
>>> df
0 1 2
List1 Value1 Value2 Value3
List2 Value1 Value2 Value3
List3 Value1 Value2 Value3
'''
# append your regex matches to the dataframe
# e.g. match any of (d,e) followed by a digit
df["match_from_column_0"] = df[0].str.extract(r'([de]\d)')
# e.g. match a digit
df["match_from_column_1"] = df[1].str.extract(r'(\d)')
# save your output as a dataframe
output = df[["match_from_column_0","match_from_column_1"]]
''' # output will look like this:
>>> output
match_from_column_0 match_from_column_1
List1 e1 2
List2 e1 2
List3 e1 2
'''
# or a dict
output_dict = output.to_dict()
'''
>>> output_dict
{'output1': {'List1': 'e1', 'List2': 'e1', 'List3': 'e1'},
'output2': {'List1': 'e2', 'List2': 'e2', 'List3': 'e2'}}
'''
解决您的2个问题:
for dict_key, dict_value in dictionary.items():
# do whatever
for value in my_list:
# do whatever
import re
for key, list_of_values in dictionary.items():
for value in list_of_values:
column_list_A = []
if re.search(regex, value):
column_list_A.append(re.search(regex, value).group(0))
else:
column_list_A.append("")
column_list_B = []
if re.search(regex, value):
column_list_B.append(re.search(regex, value).group(0))
else:
column_list_B.append("")
New_Dictionary = {"column_list_A" : column_list_A, "column_list_B" : column_list_B}
Df = pd.DataFrame.from_dict(New_Dictionary)
for column in Df:
# do your thing
一些文档的引用:
希望有所帮助!
如果你可以使用以下dictcomp:
import re
from pprint import pprint
d = {
'List1' : ['Value1', 'Value2', 'Value3'],
'List2' : ['Value1', 'Value2', 'Value3'],
'List3' : ['Value1', 'Value2', 'Value3'],
}
col = ["column_list_A", "column_list_B", "column_list_C"]
def func(a, b, c):
a = re.match(r'Val(ue\d)', a).group(1)
b = re.match(r'Valu(e\d)', b).group(1)
c = re.match(r'Value(\d)', c).group(1)
return [a, b, c]
new_d = {i: func(*j) for i, *j in zip(col, *d.values())}
pprint(new_d)
输出:
{'column_list_A': ['ue1', 'e1', '1'],
'column_list_B': ['ue2', 'e2', '2'],
'column_list_C': ['ue3', 'e3', '3']}