仅显示 php sql 列值的一部分

Question

我有一个名为“houses”的表，数据是：

SQL 表

id   name             info
1    House 1          {"adress":"Hello Street","Number":"123","City":"Rome","CAP":"12345"}
2    House 2          {"adress":"Bye Street","Number":"456","City":"Amsterdam","CAP":"6789"}
3    House 3          {"adress":"SQL Street","Number":"987","City":"Paris","CAP":"54321"}

这是我的PHP代码：

$query=mysqli_query($conn,"SELECT * FROM houses WHERE name LIKE '%$housename%'")or die(mysqli_error($conn));
$row=mysqli_fetch_array($query);

---

echo <?=($row['info'])?>;

在这种情况下它将输出整个字符串，我如何只输出字符串的一部分，例如仅输出地址：

地址：Hello Street 或“地址”：“Hello Street”

Answer 1

您有两种方法可以做到这一点，通过 SQL 或通过 PHP。

SQL：

$query=mysqli_query($conn,"SELECT id, name, substr(info, 1, 10) FROM houses WHERE name LIKE '%$housename%'")or die(mysqli_error($conn));
$row=mysqli_fetch_array($query);

PHP：

    $query=mysqli_query($conn,"SELECT * FROM houses WHERE name LIKE '%$housename%'")or die(mysqli_error($conn));
    $row=mysqli_fetch_array($query);

echo <?= substr($row['info'], 0, 10)?>;

根据您的需求进行相应调整。