如何获取搜索对象的值?
const query = new Parse.Query(Parse.User);
query.equalTo("sexo", "feminino");
query
.find()
.then(results => {
console.log(results.get("username"));
})
.catch(error => {
console.log(error);
});
TypeError:“ results.get不是函数”
results
是一个用户数组,因此,如果要显示所有用户的名称,则必须执行以下操作:
const query = new Parse.Query(Parse.User);
query.equalTo("sexo", "feminino");
query
.find()
.then(results => {
results.forEach(user => {
console.log(user.get("username"))
});
})
.catch(error => {
console.log(error);
});