来自三个文件的密码学,我具有加密的导出文件以及他们编写该密码学的应用程序

问题描述 投票:0回答:1

我有一个来自该部的文件,很难加密,并且该部已经聘请了数名德国专家来编写此加密文件。如果您知道请指导,我们只是不知道如何编写此算法。顺便说一句,我导出了文件并进行了加密应用1:“01FGz9 + M9RTPP1P / Kwcb42jThYWT8eEgE / qlpzKdhz18Ho5k + XawdsAc75vNOOcnuQmk1Nv3mRqxIps8WXh7t9nW0qc88Z + TPMeVc3GqG1fvFcC / eBah4CQO / 7onFt7GvMN + AVup4LrV5jWFt9FIwVb2RbsOXTfxVVGWkX9aEGwLy6HKhGVs4iAZEEvQM + qWc681s1K + diZ14MYcrDuu5B / mnVQPKYBI3jP7ofqtLxVHTBqSB2v4b8wYrHFIDA4bVvZFuw5dN / FmEGI2AunLGu + MbYbfqp6YVvZFuw5dN / FyxVqnm0LmtzdNyzzjvWjHVvZFuw5dN / HnGynG9nBOJVBMpnxNgCY7BVzOEHegMDwf5p1UDymASPSXVSllSqS1rkHKK14eMx0f5p1UDymASHoBu2YqDQ4lAddID1AaElV5Iqc6 + sd5k0Ni49SkXgN6L7Zrkw9AFipqVd3nO / o1Se8RSCF / VI4qJe / QL / lA7H4FErjq9pVwbZPkQ1jo4Oj6aJXdCufVqT477Q8rHmji61XE4p8VDbNTYt7h5jpokb5Lx / K8yxeyrjz1TEz / Nv2xJA7 / uicW3sbZBoNAy3Qsd9XmNYW30UjBVvZFuw5dN / FVUZaRf1oQbAvLocqEZWziEVBPG8SZBmIf5p1UDymASEZKAGsCXFzFdlVHlTR94VDko73yrNJavcwYrHFIDA4bVvZFuw5dN / FmEGI2AunLGu + MbYbfqp6YVvZFuw5dN / FyxVqnm0LmtzdNyzzjvWjHVvZFuw5dN / HnGynG9nBOJVBMpnxNgCY71PN6y4 / VZtkf5p1UDymASPSXVSllSqS1rkHKK14eMx0f5p1UDymASHoBu2YqDQ4lAddID1AaElV5Iqc6 + sd5kxf + D6p9qKh2W6z3J / XJkxgkQH + 06fsnibevV6GE8l9BMRl54HP / dMVAY + kqyIT5O2Wj / BGzkwk0" >和的,出口是1:[MES URES] 0500 = 1.01 0501 = 062 0504 = 1.014 0509 = 00.21 0510 = 13.64 0511 = 00.69 0528 = 04.18 0529 = 00134 0506 = 0.96 0507 = 1.05 0512 = 0.55 0513 = 24082019112636 0320 = spxultima123.G 0200 = 18271572 [CRC] 0500 = 49 0501 = 300 0509 = 774 0510 = 757 0511 = 738 0529 = 735 0506 = 531 0507 = 489 0512 = 491 0513 = 2036 0320 = 3567 0200 = 951所以数2是和出口是:[MESURES] 0320 = 0401 SPX5520.R = -0 5.1 0402 = + 01.8 0403 = 11012017125356 [CRC] 0320 = 1596 0401 = 736 0402 = 740 0403 = 2024请找到它并提供帮助,或者如果您在这里不能说出来,可以通过电子邮件“ [email protected]”与我联系。 com“

encryption lets-encrypt password-encryption encryption-symmetric
1个回答
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投票

由于文本是加密的结果,因此将其包装在代码块中是适当的,因此您不会丢失任何细节或篡改文本。

Example of code block
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