需要将数组输出转换为For循环之外的字符串

问题描述 投票:-1回答:1

我正在尝试为Java SE 11测试做准备中的封装,我需要帮助使我的随机名称生成器正常工作。现在,我不担心名称是否“有效”(像Xvtwg这样的真正随机名称就可以了)。我建立了一个循环,其中生成3到10之间的随机值(名称长度),然后为每个循环遍历选择0到25之间的随机索引以获取字母的随机字母。所有这些工作正常,并且我能够从循环中获取输出数组,并将其转换为循环中的串联字符串。稍后当我需要调用局部变量nameFinal作为set函数的值时,会出现问题。我试图在循环内外声明输出字符串都无济于事。我还尝试了将输出数组移到循环外(并重新定义其输出),但没有骰子。具体来说,错误显示为“ nameFinal无法解析为变量”。这是我的代码:

package RegressionTest;

import java.util.Arrays;
import java.util.Random;

public class Tester {
    public static void main(String[] args) {
        //Build random values
        Random rand = new Random();

        //Name random index 3-10 char
        int nmax = 10;
        int nmin = 3;
        int rand1 = (int)(Math.random() * (nmax - nmin + 1) + nmin);
        //Create random name from total number of letters
        //Define Array of letters
        String[] letters = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
        //Create random index to pull a random letter over the length of the random index
        int lmax = 25;
        int lmin = 0;
        //I have also tried declaring newName and nameFinal here
        for(int i = 0; i <= rand1; i++) {
            int randl = (int)(Math.random() * (lmax - lmin + 1) + lmin);
            String[] newName;
            newName[i] = letters[i];
            String nameFinal = Arrays.toString(newName);
        }
        //Concatenate array of random letters into a "name"
        //String nameFinal = Arrays.toString(newName);

        //Age random number between 1 and 100
        int amax = 100;
        int amin = 1;
        int rand2 = (int)(Math.random() * (amax - amin + 1) + amin);

        //SSN random 9 digit number
        int smax = 999999999;
        int smin = 100000000;
        int rand3 = (int)(Math.random() * (smax - smin + 1) + smin);

        //Redefine outputs to random values
        encapsulationPractice output = new encapsulationPractice();
        output.setName(nameFinal);
        output.setAge(rand2);
        output.setSSN(rand3);
    }
}

java arrays for-loop random encapsulation
1个回答
0
投票

我对您的代码做了一些更改。希望对您有帮助!

    public static void main(String[] args) {
    //Build random values
    Random rand = new Random();

    //Name random index 3-10 char
    int nmax = 10;
    int nmin = 3;
    int rand1 = (int)(Math.random() * (nmax - nmin + 1) + nmin);
    //Create random name from total number of letters
    //Define Array of letters
    String[] letters = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
    //Create random index to pull a random letter over the length of the random index
    int lmax = 25;
    int lmin = 0;

    ArrayList<String> name = new ArrayList<>(5);
    //I have also tried declaring newName and nameFinal here
    for(int i = 0; i <= rand1; i++) {
        int randl = (int)(Math.random() * (lmax - lmin + 1) + lmin);
        name.add(letters[rand1]);
    }
    //Concatenate array of random letters into a "name"
    //String nameFinal = Arrays.toString(newName);

    //Age random number between 1 and 100
    int amax = 100;
    int amin = 1;
    int rand2 = (int)(Math.random() * (amax - amin + 1) + amin);

    //SSN random 9 digit number
    int smax = 999999999;
    int smin = 100000000;
    int rand3 = (int)(Math.random() * (smax - smin + 1) + smin);

    //Redefine outputs to random values
    System.out.println(name.toString());
}
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