GSON序列化Android API 26和API 28之间的位置对象有所不同

问题描述 投票:2回答:1

我在运行API 26的仿真器实例与运行API 28的仿真器实例之间,以下代码段的工作方式不同。这是我正在运行的将GPS点数据对象转换为JSON的代码段。

GPSPointDataFinal dataFinal;
// bunch of code to put data into dataFinal

Gson gson = new GsonBuilder()
        .serializeNulls()
        .create();

String jsonFinalData = gson.toJson(dataFinal);

当我在API 26仿真器中运行此代码部分时,我得到以下JSON输出:

{"gpsData":[ 
  {"elevation":0.0,"location":{ 
    mAltitude":0.0,"mBearing":122.0,"mBearingAccuracyDegrees":0.0,"mElapsedRealtimeNanos":70951742958220,"mExtras":null,"mFieldsMask":14,"mHorizontalAccuracyMeters":20.0,"mLatitude":38.9264983,"mLongitude":-77.0151,"mProvider":"fused","mSpeed":0.0,"mSpeedAccuracyMetersPerSecond":0.0,"mTime":1575977406000,"mVerticalAccuracyMeters":0.0},
  "newSplit":false,"pointStatus":2,"time":{
    "year":2019,"month":11,"dayOfMonth":10,"hourOfDay":6,"minute":30,"second":6}
  }

请注意,所有与位置相关的数据都在此JSON字符串中。当我在API 28仿真器中运行相同的代码时,我得到以下JSON输出:

{"gpsData":[
  {"elevation":40.8,"location":{
    "mElapsedRealtimeNanos":9517448972700,"mProvider":"fused"},
  "newSplit":false,"pointStatus":2,"time":{
    "year":2019,"month":11,"dayOfMonth":10,"hourOfDay":6,"minute":32,"second":2}
  }

请注意,位置数据均不在JSON字符串中。在这两种情况下,我都逐步执行了代码,并在执行gson.toJson(dataFinal)之前确认dataFinal对象中有数据。

[调试时,我在logcat中没有看到与GSON或JSON相关的条目。知道这是什么原因以及如何解决吗?

有关信息,这是我的课程:

public class GPSPointDataFinal {

private GregorianCalendar startTime;
private ArrayList<GPSPointData> gpsData;
private CollectGPSDataServiceStatus status;
private ArrayList<Integer> splitList;

public GregorianCalendar getStartTime() {
    return startTime;
}

public void setStartTime(GregorianCalendar startTime) {
    this.startTime = startTime;
}

public ArrayList<GPSPointData> getGpsData() {
    return gpsData;
}

public void setGpsData(ArrayList<GPSPointData> gpsData) {
    this.gpsData = gpsData;
}

public CollectGPSDataServiceStatus getStatus() {
    return status;
}

public void setStatus(CollectGPSDataServiceStatus status) {
    this.status = status;
}

public ArrayList<Integer> getSplitList() {
    return splitList;
}

public void setSplitList(ArrayList<Integer> splitList) {
    this.splitList = splitList;
}

}

公共类GPSPointData {

private Location location;
private double elevation;
private GregorianCalendar time;
private int pointStatus;
private boolean newSplit;


public GPSPointData(Location location, GregorianCalendar time, int status) {
    this.location = location;
    this.elevation = elevation;
    this.time = time;
    this.pointStatus = status;
}

public GPSPointData() {
}

public Location getLocation() {
    return location;
}

public double getElevation() {
    return elevation;
}


public GregorianCalendar getTime() {
    return time;
}

public void setLocation(Location location) {
    this.location = location;
}

public void setElevation(double elevation) {
    this.elevation = elevation;
}

public void setTime(GregorianCalendar time) {
    this.time = time;
}

public int getPointStatus() {
    return pointStatus;
}

public void setPointStatus(int status) {
    this.pointStatus = status;
}

public boolean isNewSplit() {
    return newSplit;
}

public void setNewSplit(boolean newSplit) {
    this.newSplit = newSplit;
}
}
android json gps gson
1个回答
0
投票
基于上述Clownba0t的建议,通过将我需要的特定字段从位置对象提取到我的GPSPointData对象中而不包含位置对象,解决了该问题。转换为JSON后,所有字段都将包含在内。
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