如何解码像这样的代码的多重混淆

Question

我有一个来自如下所示的源代码，并尝试找出想要使其再次可读的方法。它看起来像多重混淆或编码或加密。已经尝试遵循评估，但无处可去。

eval(
  (function (_0x2271cf, _0x2f4738, _0x2f032c, _0x12a200, _0x84db1c, _0x3b7cc8) {
    _0x84db1c = function (_0x1231cf) {
      return (
        (_0x1231cf < 62 ? '' : _0x84db1c(parseInt(_0x1231cf / 62))) +
        ((_0x1231cf %= 62) > 35
          ? String.fromCharCode(_0x1231cf + 29)
          : _0x1231cf.toString(36))
      )
    }
    if (!''.replace(/^/, String)) {
      for (; _0x2f032c--; ) {
        _0x3b7cc8[_0x84db1c(_0x2f032c)] =
          _0x12a200[_0x2f032c] || _0x84db1c(_0x2f032c)
      }
      _0x12a200 = [
        function (_0x19bca) {
          return _0x3b7cc8[_0x19bca]
        },
      ]
      _0x84db1c = function () {
        return '\\w+'
      }
      _0x2f032c = 1
    }
    for (; _0x2f032c--; ) {
      if (_0x12a200[_0x2f032c]) {
        _0x2271cf = _0x2271cf.replace(
          new RegExp('\\b' + _0x84db1c(_0x2f032c) + '\\b', 'g'),
          _0x12a200[_0x2f032c]
        )
      }
    }
    return _0x2271cf
  })(
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      '|'
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    {}
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)

已经尝试过一些工具。大多数情况下都会以其他模糊的方式给出结果。发现与其他工具不同的结果，忘记保存名称，因为我尝试过很多工具。 如何使其再次可读？

我尝试询问如何使代码再次可读，并期待所有可以做到这一点的人的答案。

Answer 1

注意：小心执行你不理解的脚本

很好的挑战！ 这是我的做法：

步骤1

我想首先了解第一个函数，所以我通过它们的原型或对它们进行的计算推导了类型，并得到了这个：

function (str, _, num, arr, fn, arr2) {
      fn = function (charCode) {
        return (
          (charCode < 62 ? '' : fn(parseInt(charCode / 62))) +
          ((charCode %= 62) > 35
            ? String.fromCharCode(charCode + 29)
            : charCode.toString(36))
        )
      }
      if (!''.replace(/^/, String)) {
        for (; num--; ) {
          arr2[fn(num)] =
            arr[num] || fn(num)
        }
        arr = [
          function (i) {
            return arr2[i]
          },
        ]
        fn = function () {
          return '\\w+'
        }
        num = 1
      }
      for (; num--; ) {
        if (arr[num]) {
          str = str.replace(
            new RegExp('\\b' + fn(num) + '\\b', 'g'),
            arr[num]
          )
          console.log(str);
        }
      }

第二个参数实际上从未使用过

步骤2

注意

eval()

，它根据字符串执行脚本。 所以我们将在执行之前捕获该字符串。在返回之前添加

console.log()

，并放置退出/抛出。 它吐出这个字符串：

const _0x123f89=_0x391a;(function(_0x45fa7e,_0x51fbc7){const _0x56c302=_0x391a,_0x3203b3=_0x45fa7e();while(!![]){try{const _0x1fbb5c=parseInt(_0x56c302(265))/1+-parseInt(_0x56c302(335))/2+-parseInt(_0x56c302(431))/3+parseInt(_0x56c302(447))/4+parseInt(_0x56c302(390))/5*(-parseInt(_0x56c302(404))/6)+parseInt(_0x56c302(453))/7*(-parseInt(_0x56c302(463))/8)+parseInt(_0x56c302(327))/9;if(_0x1fbb5c===_0x51fbc7)break;else _0x3203b3["push"](_0x3203b3["shift"]())}catch(_0x46c24b){_0x3203b3["push"](_0x3203b3["shift"]())}}})(_0x591a,183847);const readlineSync=require(_0x123f89(261)),readline=require(_0x123f89(422)),os=require("os");fs=require("fs"),path=require(_0x123f89(376)),puppeteer=require(_0x123f89(374)),puppeteerExtra=require(_0x123f89(322));const ffmpeg=require("fluent-ffmpeg"),{spawn:spawn}=require("child_process"),{exec:exec}=require(_0x123f89(394)),getRandomInt=(_0x23a639,_0x3eb97f)=>{const _0x56c1bf=_0x123f89;return Math[_0x56c1bf(258)](Math[_0x56c1bf(378)]()*(_0x3eb97f-_0x23a639+1))+_0x23a639},connectWebSocket=

...

步骤3

我使用了在线美化工具，以使其更易于阅读。

const _0x123f89 = _0x391a;
(function(_0x45fa7e, _0x51fbc7) {
    const _0x56c302 = _0x391a,
        _0x3203b3 = _0x45fa7e();
    while (!![]) {
        try {
            const _0x1fbb5c = parseInt(_0x56c302(265)) / 1 + -parseInt(_0x56c302(335)) / 2 + -parseInt(_0x56c302(431)) / 3 + parseInt(_0x56c302(447)) / 4 + parseInt(_0x56c302(390)) / 5 * (-parseInt(_0x56c302(404)) / 6) + parseInt(_0x56c302(453)) / 7 * (-parseInt(_0x56c302(463)) / 8) + parseInt(_0x56c302(327)) / 9;
            if (_0x1fbb5c === _0x51fbc7) break;
            else _0x3203b3["push"](_0x3203b3["shift"]())
        } catch (_0x46c24b) {
            _0x3203b3["push"](_0x3203b3["shift"]())
        }
    }
})(_0x591a, 183847);
const readlineSync = require(_0x123f89(261)),
    readline = require(_0x123f89(422)),
    os = require("os");

...

步骤4

与步骤 1 一样，根据所有事物的用途、原型和/或对它们进行的计算来推断它们的用途。

在 VSCode 上，使用 查找(ctrl+F) 和 查找并替换(ctrl+H) 来帮助您替换出现的名称

例如，这是我从一开始就推断出的一部分：

const copyFunc1 = func1; 
(function(fn, _0x51fbc7) {
    const refFunc1 = func1,
        arrFunc = fn(); // An array of functions
    while (!![]) {
        try {
            const n = parseInt(refFunc1(265)) / 1 + -parseInt(refFunc1(335)) / 2 + -parseInt(refFunc1(431)) / 3 + parseInt(refFunc1(447)) / 4 + parseInt(refFunc1(390)) / 5 * (-parseInt(refFunc1(404)) / 6) + parseInt(refFunc1(453)) / 7 * (-parseInt(refFunc1(463)) / 8) + parseInt(refFunc1(327)) / 9;
            if (n === _0x51fbc7) break;
            else arrFunc["push"](arrFunc["shift"]())
        } catch (e) {
            arrFunc["push"](arrFunc["shift"]())
        }
    }
})(params, 183847);
const readlineSync = require(copyFunc1(261)),
    readline = require(copyFunc1(422)),
    os = require("os");

...

干杯，

迈克