当两列具有相同值时如何获取最后一条记录？ [重复]

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关闭3分钟前。

我想在相同gr_number和路线的基础上获得基于Updated_ts的最后一行

我正在使用以下查询。

select t.*
from (select  st.gr_number,st.course,st.is_active_flg,st.status,st.updated_ts

       ,sum(case when st.status = 'COMPLETED' then 1 else 0 end) over (partition by st.gr_number) as completedCourse,
      sum(case when st.status <> 'COMPLETED' and st.status <> 'APPLICATION' and st.is_active_flg = 'N' then 1 else 0 end) over (partition by st.gr_number) as IncompletCourse
      from admission_log st     
      join course cr on cr.course_id=st.course
      order by st.gr_number,st.course,st.updated_ts
     ) t
where completedCourse > 0 and IncompletCourse > 0;

此查询给我的结果为

<< img src =“ https://image.soinside.com/eyJ1cmwiOiAiaHR0cHM6Ly9pLnN0YWNrLmltZ3VyLmNvbS9VN0FhbC5wbmcifQ==” alt =“在此处输入图像描述”>

从上面的结果中，我只希望针对相同的gr_number和基于Updated_ts的课程的最后一个值

like

<< img src =“ https://image.soinside.com/eyJ1cmwiOiAiaHR0cHM6Ly9pLnN0YWNrLmltZ3VyLmNvbS9HNDJvYS5wbmcifQ==” alt =“在此处输入图像描述”>

请帮助

Answer 1

我认为您可以使用row_number()：

select t.*
from (select st.gr_number, st.course, st.is_active_flg, st.status, st.updated_ts,
            sum(case when st.status = 'COMPLETED'
                     then 1 else 0 
                end) over (partition by st.gr_number) as completedCourse,
            sum(case when st.status <> 'COMPLETED' and st.status <> 'APPLICATION' and st.is_active_flg = 'N'
                     then 1 else 0
                end) over (partition by st.gr_number) as IncompletCourse,
            row_number() over (partition by st.gr_number order by updated_ts desc) as seqnum
      from admission_log st join    
           course cr
           on cr.course_id = st.course
     ) t
where completedCourse > 0 and IncompletCourse > 0 and
      seqnum = 1;

我不认为需要您的where过滤器，但我将其留在了里面。