如何在laravel中更新多个数据库设置值

Question

1.我在视图中有一个复选框数据。

$data =["name1" =>"value1","name2"=>"value2","name3"=>"value3"]

2.我需要在控制器中更新一个模型，类似于这样。

Config::update(
          ['id'=>1,"name"=>"name1","value"=>"value1"],
          ['id'=>2,"name"=>"name2","value"=>"value2"],
          ['id'=>3,"name"=>"name2","value"=>"value3"],
       );

Answer 1

如果你想的话，你可以直接在输入数组中迭代，找到与当前id相匹配的记录，然后更新该模型实例。

foreach ($data as $record) {
    // can we find a model with that id
    if ($model = Config::find($record['id'])) {
        // update that model
        $model->update($record);
    }
}