如何使用 CodeIgniter 的查询生成器方法编写以下 SQL?
SELECT COUNT(*) AS total
FROM comments
WHERE `level`= 4
$this->db->select('count(*)');
$this->db->from('comments');
$this->db->where('level','4');
$query = $this->db->get();
echo $query->num_rows();
$this->db->select('count(*) as total');
$this->db->from('comments');
$this->db->where('level', 4);
$sql = $this->db->return_query();
/*debug*/
/*echo 'sql:: '.$sql;*/
$query = $this->db->get();
$arr = $query->row_array();
$total = $arr['total'];
$query = $this->db->query("SELECT COUNT(*) AS total FROM comments WHERE `level`= 4");
echo $query->result_array();
或
$this->db->query("SELECT COUNT(*) AS total FROM comments");
$this->db->where("`level`= 4");
您可以随时使用
$this->db->query('SELECT COUNT( * ) AS total FROM comments WHERE `level`= 4');
我想你会喜欢这样的:
$count = $this->db->where("level","4")->count_all_results("comments");
http://codeigniter.com/user_guide/database/active_record.html