Mirth Connect Channel目标排序对象的JSON数组

问题描述 投票:0回答:2

我需要对要发送到Mirth的对象进行排序。最初,排序是通过XSLT完成的(因为入站数据是XML),但是经过更改(在我的控件之外),入站数据已更改为JSON。原始排序是在我保留的目标转换中完成的。

入站JSON示例:

{
  "Id":"100001",
  "Set":
  {
    "unimportantdata1":null,
    "unimportantdata2":null,
    "unimportantdata3":"0001-01-01T00:00:00",
    "unimportantdata4":"0001-01-01T00:00:00",
    "ArrayToSort":[
      {
        "vt":"blah",
        "Num":"2",
        "desc":"dp",
        "Value":["1.1","1.2"],
        "Time":"2020-03-23T02:23:41",
        "blah": { "Name": { "LastName":"ob-ln","Firstname":"ob-fn","MiddleName":"ob-mi","Title":null}}
      },
      {
        "vt":"yadda",
        "Num":"1",
        "desc":"dp",
        "Value":["1.1","1.2"],
        "Time":"2020-03-23T02:23:41",
        "blah": { "Name":{"LastName":"ob-ln","Firstname":"ob-fn","MiddleName":"ob-mi","Title":null}}
      }
   ]}
}

我需要按“ Num”属性升序排列的ArrayToSort。

我的问题是:

  1. 在目标频道转换器中进行分类的最佳位置?
  2. 我猜要走的路是通过JavaScript,但是我不确定如何继续-建议?

提前谢谢您

javascript json mirth
2个回答
0
投票

结果证明解决方案非常简单。

在JavaScript中,您只需要执行以下操作:

msg['Set']['ArrayToSort'].sort(function(a,b){
    return a["Num"] - b["Num"];
});

logger.info(JSON.stringify(msg));

0
投票

可以使用Array.sort进行分类。并可以更新数据

let data = {
  Id: "100001",
  Set: {
    unimportantdata1: null,
    unimportantdata2: null,
    unimportantdata3: "0001-01-01T00:00:00",
    unimportantdata4: "0001-01-01T00:00:00",
    ArrayToSort: [
      {
        vt: "blah",
        Num: "2",
        desc: "dp",
        Value: ["1.1", "1.2"],
        Time: "2020-03-23T02:23:41",
        blah: {
          Name: {
            LastName: "ob-ln",
            Firstname: "ob-fn",
            MiddleName: "ob-mi",
            Title: null
          }
        }
      },
      {
        vt: "yadda",
        Num: "1",
        desc: "dp",
        Value: ["1.1", "1.2"],
        Time: "2020-03-23T02:23:41",
        blah: {
          Name: {
            LastName: "ob-ln",
            Firstname: "ob-fn",
            MiddleName: "ob-mi",
            Title: null
          }
        }
      }
    ]
  }
};
data.Set.ArrayToSort = data.Set.ArrayToSort.sort((x, y) => x.Num - y.Num);
console.log(JSON.stringify(data, null, 2));
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