2位用户输入的数字，除以输出商和余数

Question

下面的代码有效，但只除以数字中的第一个数字，余数的输出将始终为零。除法实际上不起作用，例如除以 57/12 将返回商 5.

.MODEL SMALL
.STACK 200
.DATA
    CRLF      DB  0DH, 0AH, '$'
    PROMPT1   DB  'Enter the first 2-digit number (10-99): ','$'
    PROMPT2   DB  'Enter the second 2-digit number (10-99): ','$'
    PROMPT3   DB  'The quotient is: ', '$'
    PROMPT4   DB  'The remainder is: ', '$'
    QUOTIENT  DB  ?             ; quotient
    REMAINDER DB  ?             ; remainder
    NUM1      DB  2 DUP (?)     ; array to store first number
    NUM2      DB  2 DUP (?)     ; array to store second number
.CODE
.STARTUP  
    MOV AX, @DATA
    MOV DS, AX
    ; Prompt user for first number
    LEA DX,PROMPT1              ;DISPLAY PROMPT1
    MOV AH,09H
    INT 21H  
    
    ; Read first number
    MOV CX, 2                   ; read two digits
    LEA DI, NUM1                ; point DI to first digit of NUM1
    MOV AH,01H
    READ1:
    INT 21H
    SUB AL,30H                  ; convert the character to number
    MOV [DI], AL                ; save digit in NUM1 array
    INC DI
    LOOP READ1
    
    LEA DX,CRLF                 ;MOVE CURSOR TO NEXT LINE
    MOV AH,09H
    INT 21H
    
    ; Prompt user for second number
    LEA DX,PROMPT2              ;DISPLAY PROMPT2
    MOV AH,09H
    INT 21H
    
    ; Read second number
    MOV CX, 2                   ; read two digits
    LEA DI, NUM2                ; point DI to first digit of NUM2
    MOV AH,01H
    READ2:
    INT 21H
    SUB AL,30H                  ; convert the character to number
    MOV [DI], AL                ; save digit in NUM2 array
    INC DI
    LOOP READ2
    
    ; Calculate quotient and remainder
    MOV AH, 0                   ; clear AH
    MOV AL, [NUM1]              ; copy first digit of NUM1 to AL
    MOV BL, [NUM2]              ; copy first digit of NUM2 to BL
    DIV BL                      ; divide AL by BL
    MOV QUOTIENT, AL            ; save quotient in QUOTIENT variable
    MOV REMAINDER, AH           ; save remainder in REMAINDER variable
    
    ; Display quotient and remainder
    LEA DX, CRLF
    MOV AH, 09H
    INT 21H
    
    LEA DX, PROMPT3 
    MOV AH, 09H
    INT 21H
    
    MOV DL, QUOTIENT
    ADD DL, 30H
    MOV AH, 02H
    INT 21H
    
    LEA DX, CRLF
    MOV AH, 09H
    INT 21H
    
    LEA DX, PROMPT4
    MOV AH, 09H
    INT 21H
    
    MOV DL, REMAINDER
    ADD DL, 30H
    MOV AH, 02H
    INT 21H
    
.EXIT
END

我已经尝试了我能找到的一切，但它仍然是一样的。这样做的要点是真正让我们将输入的值存储在一个数组中，然后将它相除。