C libcurl获取输出到字符串中

Question

我想将此curl函数的结果存储在变量中，该怎么办？

#include <stdio.h>
#include <curl/curl.h>

int main(void)
{
  CURL *curl;
  CURLcode res;

  curl = curl_easy_init();
  if(curl) {
    curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");
    res = curl_easy_perform(curl);

    /* always cleanup */
    curl_easy_cleanup(curl);
  }
  return 0;
}

谢谢，我这样解决了它：

#include <stdio.h>
#include <stdlib.h>
#include <curl/curl.h>

function_pt(void *ptr, size_t size, size_t nmemb, void *stream){
    printf("%d", atoi(ptr));
}

int main(void)
{
  CURL *curl;
  curl = curl_easy_init();
  if(curl) {
    curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, function_pt);
    curl_easy_perform(curl);
    curl_easy_cleanup(curl);
  }
  system("pause");
  return 0;
}

Answer 1

您可以设置一个回调函数来使用curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, myfunc);接收传入的数据块>

回调将采用用户定义的参数，您可以使用curl_easy_setopt(curl, CURLOPT_WRITEDATA, p)设置该参数>

这是将缓冲区struct string {*ptr; len}传递给回调函数并在每次调用时使用realloc（）增大该缓冲区的代码段。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <curl/curl.h>

struct string {
  char *ptr;
  size_t len;
};

void init_string(struct string *s) {
  s->len = 0;
  s->ptr = malloc(s->len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "malloc() failed\n");
    exit(EXIT_FAILURE);
  }
  s->ptr[0] = '\0';
}

size_t writefunc(void *ptr, size_t size, size_t nmemb, struct string *s)
{
  size_t new_len = s->len + size*nmemb;
  s->ptr = realloc(s->ptr, new_len+1);
  if (s->ptr == NULL) {
    fprintf(stderr, "realloc() failed\n");
    exit(EXIT_FAILURE);
  }
  memcpy(s->ptr+s->len, ptr, size*nmemb);
  s->ptr[new_len] = '\0';
  s->len = new_len;

  return size*nmemb;
}

int main(void)
{
  CURL *curl;
  CURLcode res;

  curl = curl_easy_init();
  if(curl) {
    struct string s;
    init_string(&s);

    curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writefunc);
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
    res = curl_easy_perform(curl);

    printf("%s\n", s.ptr);
    free(s.ptr);

    /* always cleanup */
    curl_easy_cleanup(curl);
  }
  return 0;
}

以下答案是使用C ++的C ++方法，而不是以空终止的字符串。它仍然使用回调函数（无法解决），但也使用try / catch处理分配错误。

std::string

从此处阅读手册：

#include <iostream>
#include <string>
#include <curl/curl.h>

size_t CurlWrite_CallbackFunc_StdString(void *contents, size_t size, size_t nmemb, std::string *s)
{
    size_t newLength = size*nmemb;
    try
    {
        s->append((char*)contents, newLength);
    }
    catch(std::bad_alloc &e)
    {
        //handle memory problem
        return 0;
    }
    return newLength;
}
int main()
{
    CURL *curl;
    CURLcode res;

    curl_global_init(CURL_GLOBAL_DEFAULT);

    curl = curl_easy_init();
    std::string s;
    if(curl)
    {

        curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");

        curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L); //only for https
        curl_easy_setopt(curl, CURLOPT_SSL_VERIFYHOST, 0L); //only for https
        curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, CurlWrite_CallbackFunc_StdString);
        curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
        curl_easy_setopt (curl, CURLOPT_VERBOSE, 1L); //remove this to disable verbose output


        /* Perform the request, res will get the return code */
        res = curl_easy_perform(curl);
        /* Check for errors */
        if(res != CURLE_OK)
        {
            fprintf(stderr, "curl_easy_perform() failed: %s\n",
                    curl_easy_strerror(res));
        }

        /* always cleanup */
        curl_easy_cleanup(curl);
    }

    std::cout<<s<<std::endl;

    std::cout<< "Program finished!" << std::endl;
}

，我认为您需要多次调用CURL_SETOPT，第一个是要处理的URL，第二个是类似的东西：

http://curl.haxx.se/libcurl/c/curl_easy_setopt.html

function_ptr与该签名匹配的地方：

curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, function_ptr);

这里发生的是，您表示一个回调函数，当libcurl有一些输出要从调用的任何传输写入时，libcurl就会调用该函数。您可以获取它以自动写入文件，或向其传递指向将自行处理输出的函数的指针。使用此功能，您应该能够将各种输出字符串组装成一个片段，然后在程序中使用它们。

我不确定您可能需要设置哪些其他选项/其他因素会影响您希望应用程序的运行方式，因此请在该页面中仔细查看。

这里是size_t function( void *ptr, size_t size, size_t nmemb, void *stream) 接受的答案的C ++风味>

alex-jasmin

Answer 2

以下答案是使用C ++的C ++方法，而不是以空终止的字符串。它仍然使用回调函数（无法解决），但也使用try / catch处理分配错误。

Answer 3

从此处阅读手册：

#include <iostream>
#include <string>
#include <curl/curl.h>

size_t CurlWrite_CallbackFunc_StdString(void *contents, size_t size, size_t nmemb, std::string *s)
{
    size_t newLength = size*nmemb;
    try
    {
        s->append((char*)contents, newLength);
    }
    catch(std::bad_alloc &e)
    {
        //handle memory problem
        return 0;
    }
    return newLength;
}
int main()
{
    CURL *curl;
    CURLcode res;

    curl_global_init(CURL_GLOBAL_DEFAULT);

    curl = curl_easy_init();
    std::string s;
    if(curl)
    {

        curl_easy_setopt(curl, CURLOPT_URL, "curl.haxx.se");

        curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L); //only for https
        curl_easy_setopt(curl, CURLOPT_SSL_VERIFYHOST, 0L); //only for https
        curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, CurlWrite_CallbackFunc_StdString);
        curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
        curl_easy_setopt (curl, CURLOPT_VERBOSE, 1L); //remove this to disable verbose output


        /* Perform the request, res will get the return code */
        res = curl_easy_perform(curl);
        /* Check for errors */
        if(res != CURLE_OK)
        {
            fprintf(stderr, "curl_easy_perform() failed: %s\n",
                    curl_easy_strerror(res));
        }

        /* always cleanup */
        curl_easy_cleanup(curl);
    }

    std::cout<<s<<std::endl;

    std::cout<< "Program finished!" << std::endl;
}

，我认为您需要多次调用CURL_SETOPT，第一个是要处理的URL，第二个是类似的东西：

Answer 4

这里是size_t function( void *ptr, size_t size, size_t nmemb, void *stream) 接受的答案的C ++风味>

alex-jasmin