如何在点击reactjs时重新加载表格

问题描述 投票:0回答:1

我想知道如何仅重新加载表格,而不是整个页面的反应。我尝试过使用

history.go(0);
但是,它会重新加载整个页面,请检查如何重新加载它,如果我要使用
forceUpdate
,根据研究,您应该避免使用它。我正在尝试做一个 AJAX,但我不知道该把什么放在哪里;它与 PHP 有很大不同。

我的代码

onclick

 handleSubmit( name, address,department){

 const laman = {
      'Employee_Name': name,
      'Address': address,
      'Department': department
    }
    return fetch('http://localhost:5118/api/employeedetails/PostEmployeeDetail?', {
        method: 'POST',
        headers: {
        'Content-Type': 'application/json'
        },
        body: JSON.stringify(laman)
    })
    .then(function(response) {
      console.log(response)
      return response.json();
    })
    .then(function (result) {
      history.go(0);
    })
    .catch(function(error) {
      console.log(error);

    })
}

这是 onclick 按钮加上表格本身的代码

render() {
     const isEnabled = this.canBeSubmitted();
    let {jsonReturnedValue} = this.state;
  return(
    <div>
        <div className="container">   
          <h1> Listof Employees </h1>
            <button className ='btn btn-warning right ' data-toggle="modal" data-target="#AddEmployee"> Add an Employee</button>
             <table className= "table table-bordered" id="result"> 
                <tbody>
                 <tr>
                      <th>ID</th>
                      <th>Name</th>
                      <th>Address</th>
                      <th>Update</th>
                      <th>Delete</th>
                 </tr>
                    {jsonReturnedValue.map((d,i) => this.renderItem(d,i))}
                </tbody>
            </table>
          </div>

      {/*Updating*/}

    <div className="modal fade" id="UpdateEmployee" role="dialog">
           <div className="modal-dialog">
             <div className="modal-content">
                <div className="modal-header">
                   <button type="button" className="close" data-dismiss="modal">&times;</button>
                  <h4 className="modal-title">ADD  Employee</h4>
            </div>
<form>

        <div className="container">
          <div className="modal-body">
              <table> 
              <tbody>
              <tr>
              <td>Name</td>
              <td>
              <input type="text"
                    ref="Employee_Name"
                    onChange={(e) => this.handleChange(e, "Employee_Name")}
                    required
                    /> 
              </td>
              </tr>
              <tr>
              <td>Address</td>
              <td>
               <input type="text"
                     ref="Address"
                    onChange={(e) => this.handleChange(e, "Address")}
                    required
                     />
              </td>
              </tr>
              <tr>
              <td>Department</td>
              <td>
               <input type="text"
                      
                      onChange={(e) => this.handleChange(e, "Department")}
                      required
              /> 
              </td>
              </tr>
              </tbody>
              </table>

          </div>
          </div>
          <div className="modal-footer">
            <input type="button" className="btn btn-info"disabled={!isEnabled} 
                    onClick = { this.handleSubmit.bind(
                                this, this.state.Employee_Name,
                                this.state.Address,
                                this.state.Department)
                                 }
                               value =" Add Employee"
                               data-dismiss="modal"/>
            <button type="button" className="btn btn-default" data-dismiss="modal" >Close</button>
          </div>

            </form>

PS:它也在同一页面..我不知道如何称呼它的原因。

javascript reactjs asp.net fetch-api
1个回答
0
投票

在您的

ajax
通话中,通话成功后获得回复并致电
setState
并收到新回复。

现在将做出反应

re-render
并且您的组件将使用来自 ajax 调用的新数据进行更新。

无需打电话

history.go(0)

我假设有一个

TableComponent
可以呈现表格结构。
TableComponent
data
组件接收 Test 作为
prop

一旦通过 ajax 调用获得新数据,该数据就会传递给

TableComponent
TableComponent
重新呈现自身。

在这种情况下,不会发生整个页面重新渲染,仅在状态更改的地方发生更改。

以下面的代码片段为例。

class Test extends React.Component {

   constructor(){
     super();
     this.state = {
        data:[]
     };
   }
   
   handleChange = (event, name) => {
    // set state here
   }
  
 handleSubmit( name, address,department) {

 const laman = {
      'Employee_Name': name,
      'Address': address,
      'Department': department
    }
    return fetch('http://localhost:5118/api/employeedetails/PostEmployeeDetail?', {
        method: 'POST',
        headers: {
        'Content-Type': 'application/json'
        },
        body: JSON.stringify(laman)
    })
    .then(function(response) {
      console.log(response)
      return response.json();
    })
    .then(function (result) {
      this.setState({data:result}); // <--------
      // as soon as you will call setState rerender will occur
  
    })
    .catch(function(error) {
      console.log(error);

    })
}

  render() {
    return ( 
    <div>
           <form>
<div className="container">
      <div className="modal-body">
          <table> 
          <tbody>
          <tr>
          <td>Name</td>
          <td>
          <input type="text"
                ref="Employee_Name"
                onChange={(e) => this.handleChange(e, "Employee_Name")}
                required
                /> 
          </td>
          </tr>
          <tr>
          <td>Address</td>
          <td>
           <input type="text"
                 ref="Address"
                onChange={(e) => this.handleChange(e, "Address")}
                required
                 />
          </td>
          </tr>
          <tr>
          <td>Department</td>
          <td>
           <input type="text"

                  onChange={(e) => this.handleChange(e, "Department")}
                  required
          /> 
          </td>
          </tr>
          </tbody>
          </table>

      </div>
      </div>
      <div className="modal-footer">
        <input type="button" className="btn btn-info" disabled={!isEnabled} 
           onClick = { this.handleSubmit.bind(
                            this, this.state.Employee_Name,
                            this.state.Address,
                            this.state.Department)
                      }
            value =" Add Employee"
            data-dismiss="modal"/>
        <button type="button" className="btn btn-default" data-dismiss="modal" >Close</button>
      </div>

        </form>
        
       // your table component or jsx goes here

        // render your table based on state -- data
        <TableComponent data={this.state.data} />
    </div>
    );
  }
}

ReactDOM.render( <Test /> ,
  document.getElementById('root')
);
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

<div id="root"></div>

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