在Sqlserver 2019脚本中, 我有一张员工休假表,如下格式
Empcode LeaveFrom LeaveTo
A 23/07/2023 01/08/2023
02/08/2023 03/08/2023
04/08/2023 04/08/2023
B 10/07/2023 01/08/2023
02/08/2023 03/08/2023
输出结果应该是
A 23/07/2023 04/08/2023
B 10/07/2023 03/08/2023
我已经使用了
leave function
,但仍然没有得到我预期的结果。寻找建议。
我已经尝试过
Leave function, row_number(), rank, dense_rank
我没找到你,但你可以试试这个:) SELECT Empcode, MIN(LeaveDate) AS MinLeaveDate, MAX(LeaveDate) AS MaxLeaveDate 从 ( SELECT Empcode、LeaveFrom AS LeaveDate FROM Leaves 联盟 从叶子中选择 Empcode、LeaveTo AS LeaveDate ) AS 组合叶 按 Empcode 分组;