按另一个表选择每个行连接的最小值

Question

我有下表：

           Table1                         Table2        
CardNo  ID   Record   Date          ID    Name      Dept    
1      101   8.00    11/7/2013      101   Danny     Green   
2      101   13.00   11/7/2013      102   Tanya     Red 
3      101   15.00   11/7/2013      103   Susan     Blue    
4      102   11.00   11/7/2013      104   Gordon    Blue    
5      103   12.00   11/7/2013                  
6      104   12.00   11/7/2013                  
7      104   18.00   11/7/2013                  
8      101    1.00   12/7/2013                  
9      101   10.00   12/7/2013                  
10     102    0.00   12/7/2013                  
11     102    1.00   12/7/2013                  
12     104    3.00   12/7/2013                  
13     104    4.00   12/7/2013  

我希望结果是这样的：

Name    Dept    Record
Danny   Green   8.00
Tanya   Red     11.00
Susan   Blue    12.00
Gordon  Blue    18.00

其中结果仅显示每个“名称”的“记录”的最小值，并按所选日期过滤。我正在使用SQL。

Answer 1

采用：

select t2.Name, t2.Dept, min(t1.Record)
from table1 t1
join table2 t2 on t2.ID = t1.ID
group by t2.ID, t2.Name, t2.Dept

要么

select t2.Name, t2.Dept, a.record
from table2 t2
join
(
    select t1.ID, min(t1.Record) [record]
    from table1 t1
    group by t1.ID
)a
on a.ID = t2.ID

要过滤查询，请添加where子句，例如：

select t2.Name, t2.Dept, min(t1.Record)
from table1 t1
join table2 t2 on t2.ID = t1.ID
where t1.Date = '11/7/2013'
group by t2.ID, t2.Name, t2.Dept

Answer 2

请试试：

Select
    b.Name,
    b.Dept,
    MIN(Record) Record
from
    Table1 a join Table2 b on a.ID=b.ID
GROUP BY b.Name,
    b.Dept

Answer 3

select 
        b.Name,
        b.Dept,
        min(a.Record)
from Table1 a,Table2 b 
where
        a.ID=b.ID 
group by 
        a.Record