如何使用PHP cURL发布JSON数据?

问题描述 投票:104回答:6

这是我的代码,

$url = 'url_to_post';
$data = array(
    "first_name" => "First name",
    "last_name" => "last name",
    "email"=>"[email protected]",
    "addresses" => array (
        "address1" => "some address",
        "city" => "city",
        "country" => "CA",
        "first_name" =>  "Mother",
        "last_name" =>  "Lastnameson",
        "phone" => "555-1212",
        "province" => "ON",
        "zip" => "123 ABC"
    )
);
$data_string = json_encode($data);
$ch=curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));
curl_setopt($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER,
    array(
        'Content-Type:application/json',
        'Content-Length: ' . strlen($data_string)
    )
);

$result = curl_exec($ch);
curl_close($ch);

在其他页面,我正在检索发布数据。

    print_r ($_POST);

输出是

HTTP/1.1 200 OK
Date: Mon, 18 Jun 2012 07:58:11 GMT
Server: Apache
X-Powered-By: PHP/5.3.6
Vary: Accept-Encoding
Connection: close
Content-Type: text/html

Array ( ) 

所以,即使在我自己的服务器上,我也没有获得正确的数据,它是空数组。我想在http://docs.shopify.com/api/customer#create上使用json实现REST

php json rest curl
6个回答
164
投票

你正在错误地发布json - 但即使它是正确的,你也无法使用print_r($_POST)read why here)进行测试。相反,在第二页上,您可以使用file_get_contents("php://input")来捕获传入的请求,echo '<pre>'.print_r(json_decode(file_get_contents("php://input")),1).'</pre>'; 将包含POSTed json。要以更易读的格式查看收到的数据,请尝试以下操作:

Content-Type:application/json

在您的代码中,您指示$ch = curl_init( $url ); # Setup request to send json via POST. $payload = json_encode( array( "customer"=> $data ) ); curl_setopt( $ch, CURLOPT_POSTFIELDS, $payload ); curl_setopt( $ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json')); # Return response instead of printing. curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true ); # Send request. $result = curl_exec($ch); curl_close($ch); # Print response. echo "<pre>$result</pre>"; ,但您不是json编码所有POST数据 - 只有“customer”POST字段的值。相反,做这样的事情:

a third-party library

旁注:您可能会受益于使用$url = 'url_to_post'; $data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) ); $postdata = json_encode($data); $ch = curl_init($url); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json')); $result = curl_exec($ch); curl_close($ch); print_r ($result); 而不是直接与Shopify API接口。


11
投票
curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));

这段代码对我有用。你可以试试...


10
投票

更换

$data_string = json_encode(array("customer"=>$data));
//Send blindly the json-encoded string.
//The server, IMO, expects the body of the HTTP request to be in JSON
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);

有:

$jsonStr = file_get_contents("php://input"); //read the HTTP body.
$json = json_decode($jsonStr);

我不明白你的意思是“其他页面”,我希望它是在'url_to_post'的页面。如果该页面是用PHP编写的,那么上面发布的JSON将以下面的方式阅读:

$url = 'url_to_post';

$data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" =>  "Mother","last_name" =>  "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );

$data_string = json_encode(array("customer" =>$data));

$ch = curl_init($url);

curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);

curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

$result = curl_exec($ch);

curl_close($ch);

echo "$result";

6
投票

请尝试以下代码: -

<?php 
 $url = 'http://localhost/test/page2.php';
    $data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" =>  "Mother","last_name" =>  "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
    $ch=curl_init($url);
    $data_string = urlencode(json_encode($data));
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
    curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string));


    $result = curl_exec($ch);
    curl_close($ch);

    echo $result;
?>

2
投票

试试这个例子。

<?php
$datastring = $_POST['customer'];
$data = json_decode( urldecode( $datastring));

?>

你的page2.php代码

$url = 'url_to_post';
// this is only part of the data you need to sen
$customer_data = array("first_name" => "First name","last_name" => "last name","email"=>"[email protected]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" =>  "Mother","last_name" =>  "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) );
// As per your API, the customer data should be structured this way
$data = array("customer" => $customer_data);
// And then encoded as a json string
$data_string = json_encode($data);
$ch=curl_init($url);

curl_setopt_array($ch, array(
    CURLOPT_POST => true,
    CURLOPT_POSTFIELDS => $data_string,
    CURLOPT_HEADER => true,
    CURLOPT_HTTPHEADER => array('Content-Type:application/json', 'Content-Length: ' . strlen($data_string)))
));

$result = curl_exec($ch);
curl_close($ch);

-1
投票

试试这样:

qazxswpoi

你忘记的关键是json_encode你的数据。但是你也可以发现使用curl_setopt_array通过传递一个数组来一次设置所有curl选项很方便。

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