输入他们的个人资料后,我试图更新一些用户。
这是将我转移到他们的个人资料页面的按钮。一切正常,直到我尝试更新一些信息。
echo "<td>" .'<a href="profile.php?id=' . $row['id']. '"><button class="view">View Profile</button></a>'. "</td>";
这是个人资料页面:
$id = $_GET['id'];
$db = mysqli_connect('localhost', '###', '###', '###');
$sql = "SELECT * FROM clients WHERE id='".$id."' ";
$result = mysqli_query($db, $sql);
$resultCheck = mysqli_num_rows($result);
if ($resultCheck > 0) {
echo "<table>
<tr>
<th> Naam </th>
<th> id </th>
<th> email </th>
</tr>";
while ($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
$name = $row['name'];
$email = $row['email'];
}
}
if (isset($_POST['pinfo'])) {
$query = "UPDATE clients SET name=? , email=?
WHERE id=?";
$stmt = mysqli_prepare($db, $query);
mysqli_stmt_bind_param($stmt, 'sss', $_POST['name'], $_POST['email'], $id);
mysqli_stmt_execute($stmt);
}
尝试更新后,我仅收到"Undefined index: id"
的错误
您的ID字段未初始化或出于某种原因而休息。尝试将ID设置为隐藏的表单元素,例如:
<input stype="diplay: none;" name="id" value='"+$id+"' />
并将其从$ _POST传递到mysql_stmt_bind_param,例如
mysqli_stmt_bind_param($stmt, 'sss', $_POST['name'], $_POST['email'], $_POST['id']);