我已经编写了一个网格,但现在我想更改网格中单个矩形的颜色。
x = 5
y = 5
height = 30
width = 50
size = 20
color = (255,255,255)
new_color = (255,255,0)
screen.fill((0,0,0))
def draw_grid():
for y in range(height):
for x in range(width):
rect = pygame.Rect(x * (size + 1),y * (size + 1),size,size)
pygame.draw.rect(screen,color,rect)
x += 20
rects.append((rect,color))
y += 20
rects = []
colored_rects = []
while 1:
for event in pygame.event.get():
if event.type == QUIT:
sys.exit()
draw_grid()
if pygame.mouse.get_pressed()[0]:
mouse_pos = pygame.mouse.get_pos()
for i,(rect,color) in enumerate(rects):
if rect.collidepoint(mouse_pos):
rects[i] = (rect,new_color)
colored_rects.append((rect,new_color))
for rect,color in rects:
pygame.draw.rect(screen,color,rect)
for rect,new_color in colored_rects:
pygame.draw.rect(screen,new_color,rect)
pygame.display.flip()
clock.tick()
现在我只想点击改变一个矩形,但以后它们必须自动改变(例如当三个矩形接触相同颜色时,它们必须变成白色)。我已经更新了一些,但仍然存在一些问题。例如:你必须点击矩形直到它改变颜色,而改变颜色需要很长时间。
一个解决方案是将矩形连同它们的颜色一起存储在元组中。如果按下鼠标按钮,您将遍历
rectangles
列表,如果一个矩形与鼠标发生碰撞,您将使用该矩形和新颜色创建一个元组并替换当前索引处的元组。
import sys
import pygame as pg
def main():
screen = pg.display.set_mode((640, 480))
clock = pg.time.Clock()
height = 30
width = 50
size = 20
color = (255, 255, 255)
new_color = (255, 255, 0)
rectangles = []
for y in range(height):
for x in range(width):
rect = pg.Rect(x * (size+1), y * (size+1), size, size)
# The grid will be a list of (rect, color) tuples.
rectangles.append((rect, color))
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
if pg.mouse.get_pressed()[0]:
mouse_pos = pg.mouse.get_pos()
# Enumerate creates tuples of a number (the index)
# and the rect-color tuple, so it looks like:
# (0, (<rect(0, 0, 20, 20)>, (255, 255, 255)))
# You can unpack them directly in the head of the loop.
for index, (rect, color) in enumerate(rectangles):
if rect.collidepoint(mouse_pos):
# Create a tuple with the new color and assign it.
rectangles[index] = (rect, new_color)
screen.fill((30, 30, 30))
# Now draw the rects. You can unpack the tuples
# again directly in the head of the for loop.
for rect, color in rectangles:
pg.draw.rect(screen, color, rect)
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
pg.init()
main()
pg.quit()
sys.exit()