$mysqli=new mysqli("localhost", "***", "***","***") or die(mysql_error());
function checklogin($username, $password){
global $mysqli;
$result = $mysqli->prepare("SELECT * FROM users WHERE username = ?");
$result->bind_param("s", $username);
$result->execute();
if($result != false){
$dbArray=mysql_fetch_array($result);
mysqli_fetch_array
代替mysql_fetch_array
。签出$result->fetch_array()
我只是犯了同样的错误,但是当我将其更改为mysqli_fetch_array()时,它解决了。