通过id /电子邮件在graphQL中查找一个元素

问题描述 投票:-1回答:1

我正在尝试为graphQL创建一个findOneByEmail / id。我看到了几个问题,博客文章和视频,但它们对我的情况没有帮助。我知道我必须添加一个过滤器,但是我必须缺少一些内容

这是我的resolvers

const users = [
  {id: 1, email:'[email protected]',password:'zaq1@WSX', pons:[{value:'test'}]},
  {id: 2, email:'[email protected]',password:'ZAQ!2wsx', pons:[{value:'tset'}]}
];
const pons = [{value: 'test'}];
module.exports = {
  Query: {
    users: () => users,
    pons: () => pons,
  }
};

typeDefs

const {gql} = require('apollo-server-express');

module.exports = gql`  
  type Pon {
      value: String!
  }
  type User {
    id: Int
    email: String!
    password: String!
    pons: [Pon]!
  }
  type Query {
      findUser(id: Int): [User]
      users: [User]
      pons: [Pon]
  }
`;

app.js

const express = require('express');
const { ApolloServer } = require('apollo-server-express');
const typeDefs = require('./graphql/typeDefs.js');
const resolvers = require('./graphql/resolvers.js');

const server = new ApolloServer({typeDefs, resolvers});

const app = express();
server.applyMiddleware({ app });

app.listen({ port: 4000 }, () =>
  console.log(`🚀 Server ready at http://localhost:4000${server.graphqlPath}`)
);

我将expressapollo-server-express一起使用。

我尝试添加users(id: Int)users(email: String),但没有成功。您可以在findUser查询中看到它。我像这样调用查询:

query{
  findUser(id: 1) {
    email
    pons {
      value
    }
  }
}

在GQL游乐场。

我希望能够过滤服务器上而不是客户端上的数据,并且无法在任何地方找到解决方案

javascript express graphql apollo apollo-server
1个回答
0
投票

您可以在GraphQL解析器中获取id参数并通过它查询用户。

例如

const express = require('express');
const { ApolloServer } = require('apollo-server-express');
const { gql } = require('apollo-server-express');

const users = [
  { id: 1, email: '[email protected]', password: 'zaq1@WSX', pons: [{ value: 'test' }] },
  { id: 2, email: '[email protected]', password: 'ZAQ!2wsx', pons: [{ value: 'tset' }] },
];
const pons = [{ value: 'test' }];

const typeDefs = gql`
  type Pon {
    value: String!
  }
  type User {
    id: Int
    email: String!
    password: String!
    pons: [Pon]!
  }
  type Query {
    findUser(id: Int): User
    users: [User]
    pons: [Pon]
  }
`;

const resolvers = {
  Query: {
    users: () => users,
    pons: () => pons,
    findUser: (_, { id }) => users.find((u) => u.id === id),
  },
};

const server = new ApolloServer({ typeDefs, resolvers });

const app = express();
server.applyMiddleware({ app });

app.listen({ port: 4000 }, () => console.log(`🚀 Server ready at http://localhost:4000${server.graphqlPath}`));

在GraphQL游乐场查询:

query{
  findUser(id: 1){
    email 
    pons {
      value
    }
  }
}

响应:

{
  "data": {
    "findUser": {
      "email": "[email protected]",
      "pons": [
        {
          "value": "test"
        }
      ]
    }
  }
}
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