PHP更新未按预期运行[关闭]

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[<6天前关闭。

在我的MySQL数据库中，我有一列名为CHECK的列，我的值只有1或0，当一个用户登录我的网站时，此值输入1，而当他注销时，该值输入0。但是我没有任何值知道为什么这段代码不想在我的栏中输入1。

或者我可以检查一个用户是否已经登录吗？

这是我的数据库表：

if ($username && $password_sha1) {
    $query = mysqli_query ( $conn, "SELECT * FROM portofoliu_table WHERE account= '$username'" );
    $numrows = mysqli_num_rows ( $query );

    $val = 1;

    if ($numrows != 0) {

        while ( $row = mysqli_fetch_assoc ( $query ) ) {
            $db_account = $row ['account'];
            $db_password = $row ['password'];
        }
        if ($username == $db_account && $password_sha1 == $db_password) {

            //----------------------------------------HERE--------------------------------------------------------
            mysqli_query ( $conn, "UPDATE portofoliu_table SET check = '$val' WHERE account= '$username'" );
            //----------------------------------------------------------------------------------------------------

            $_SESSION ['account'] = $username;
            $_SESSION ["logged"] = true;

            header ( "location: AboutMe.php" );
            exit ();
        } else {
            echo "<div id='err'>Your password is incorrected</div>";
        }
        $_SESSION ["logged"] = false;
        exit ();
    } else {
        die ( "<div id='err'>That user don't exists</div>" );
    }
} else {
    die ( "<div id='err'>Please enter a username and password</div>" );
}

Answer 1

我认为这里的问题是变量范围。

  while ( $row = mysqli_fetch_assoc ( $query ) ) {
             $db_account = $row['account'];
             $db_password = $row['password'];
              if ($username == $db_account && $password_sha1 ==$db_password) {
                //place rest of code here.
              }
         }

$db_account和$db_passwords变量不在范围内，因此无法使用。像上面一样尝试更改。

Answer 2

尝试一下？

<?
if ($username && $password_sha1) {
    $query = mysqli_query ( $conn, "SELECT * FROM portofoliu_table WHERE `account`='$username'" );
    $numrows = mysqli_num_rows ( $query );

    $val = 1;

    if ($numrows > 0) {

        while ( $row = mysqli_fetch_assoc ( $query ) ) {
            $db_account = $row['account'];
            $db_password = $row['password'];
        }
        if ($username == $db_account && $password_sha1 == $db_password) {

            //----------------------------------------HERE--------------------------------------------------------
            mysqli_query ( $conn, "UPDATE portofoliu_table SET `check`='$val' WHERE `account`='$username'" );
            //----------------------------------------------------------------------------------------------------

            $_SESSION['account'] = $username;
            $_SESSION["logged"] = true;

            header ( "location: AboutMe.php" );
            exit ();
        } else {
            echo "<div id='err'>That password is incorrect.</div>";
        }
        $_SESSION["logged"] = false;
        exit ();
    } else {
        die ( "<div id='err'>That user does not exist.</div>" );
    }
} else {
    die ( "<div id='err'>Please enter a username and password</div>" );
}
?>