剧作家Python没有得到回应

Question

当我等待页面上进行的 API 调用的响应时，PlayWright 永远不会收到响应。我在多次尝试等待不同页面上的响应时看到过这种情况，但这里有一些示例代码，可以将其范围缩小到我希望的易于复制的情况。

代码超时

from playwright.sync_api import Page
from playwright.sync_api import sync_playwright

import json


with sync_playwright() as p:

    browser = p.chromium.launch(headless=False)
    page = browser.new_page()

    # Goto playwright homepage and press search box:
    page.goto("https://playwright.dev/")
    page.get_by_role('button', name='Search').click()

    # Catching response associated with filling searchfield:
    with page.expect_response("**.algolia.net/**") as response:

        # Fill a letter in searchbox to trigger the post-request:
        page.get_by_placeholder('Search docs').fill('A')

        # Printing the value of the response as a python json object:
        print(response.value.json())

        # Printing the value of the response as raw json:
        print(json.dumps(response.value.json()))

这是响应超时时出现的错误消息

Exception has occurred: InvalidStateError
invalid state
  File "C:\Users\ronwa\Documents\playwright-test\pwright-search.py", line 23, in <module>
    print(response.value.json())
          ^^^^^^^^^^^^^^
playwright._impl._errors.TimeoutError: Timeout 30000ms exceeded while waiting for event "response"
=========================== logs ===========================
waiting for response **.algolia.net/**
============================================================

During handling of the above exception, another exception occurred:

  File "C:\Users\ronwa\Documents\playwright-test\pwright-search.py", line 7, in <module>
    with sync_playwright() as p:
asyncio.exceptions.InvalidStateError: invalid state

Answer 1

我认为你不能用

**

删除协议，只能删除路径块。尝试提供它：

from playwright.sync_api import sync_playwright


with sync_playwright() as p:
    browser = p.chromium.launch()
    page = browser.new_page()
    page.goto("https://playwright.dev/")
    page.get_by_role("button", name="Search").click()

    with page.expect_response("https://*.algolia.net/**") as response:
        page.get_by_placeholder("Search docs").fill("A")

    print(response.value.json())