我一直在尝试学习在我的项目中使用 firebase 数据库。但是,我无法让它工作,因为从我的 firebase 读取数据时似乎出现错误。我只看了视频教程并从互联网上阅读了一些信息,所以我仍然不确定我在做什么。如果有人能够指出我的代码中的实际错误,我将非常感激。
const db = getDatabase();
var tBody = document.querySelector("#tbody1");
var appointmentID = 0;
tBody.innerHTML = "";
function AddRequestToTable(name, email, phone, date, time, service, status) {
let tRow = document.createElement("tr");
let td1 = document.createElement("td");
let td2 = document.createElement("td");
let td3 = document.createElement("td");
let td4 = document.createElement("td");
let td5 = document.createElement("td");
let td6 = document.createElement("td");
let td7 = document.createElement("td");
td1 = ++appointmentID;
td2 = name;
td3 = email;
td4 = phone;
td5 = date + " " + time;
td6 = service;
td7 = status;
tRow.appendChild(td1);
tRow.appendChild(td2);
tRow.appendChild(td3);
tRow.appendChild(td4);
tRow.appendChild(td5);
tRow.appendChild(td6);
tRow.appendChild(td7);
tBody.appendChild(tRow);
}
function AddAllRequeststoTable(AppointmentRequests) {
tBody.innerHTML = "";
AppointmentRequests.array.forEach((element) => {
AddRequestToTable(
element.name,
element.email,
element.phone,
element.date,
element.time,
element.service,
element.status,
);
});
}
function GetAllDataOnce() {
const dbRef = ref(db, "appointmentForm");
get(dbRef, child(db)) = ((snapshot) => {
var requests = [];
snapshot.forEach((childSnapshot) => {
requests.push(childSnapshot.val());
});
AddAllRequeststoTable(requests);
});
}
window.onload = GetAllDataOnce();
它说错误出在这部分的某个地方......
function GetAllDataOnce() {
const dbRef = ref(db, "appointmentForm");
get(dbRef, child(db)) = ((snapshot) => {
var requests = [];
snapshot.forEach((childSnapshot) => {
requests.push(childSnapshot.val());
});
AddAllRequeststoTable(requests);
});
}
我已经尝试了超过12个小时,但仍然无济于事。
您的 GetAllDataOnce 应该是以下内容:
get(child(dbRef, `DBName/${childUID}`)).then((snapshot) => {
}