为什么我的卷毛要求不起作用我做错了什么

问题描述 投票:0回答:1

我究竟做错了什么?

我正试图从下拉列表中创建一个新的curl请求我做错了什么?

<form action="" method="POST">
     <div class="form-group">
        <label for="comment">Select Page:</label>
        <select class="form-control" name="pagecall" id="pagecall" style="width:75%;float:right;" onchange="davsele(this.value);">
            <?php
                $totalPage = $dataget['total'] / 20;
                for($i=1;$i<=$totalPage;$i++)
                {
                    $selc = ($getPageCount==$i)?'selected':'';
                    echo "<option value=".$i." $selc>Page No. ".$i."</option>";
                }
            ?>
        </select>
    </div>
</form>

我试图打电话的功能

<?php

    function proCall() {

    $ch = curl_init();

    $getPageCount == sval;

    curl_setopt($ch, CURLOPT_URL,"https://products-export-api.g2a.com/v1/products?page=$getPageCount");
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    $server_output = curl_exec($ch);

        //Gets the API data
    $response = curl_exec($curl);
    $err = curl_error($curl);
    //curl_close($curl);
    $dataget = json_decode($response,true);
    print_r($dataget);
    echo "test";
    curl_close ($ch);
    }
?>

什么是从下拉列表发送到js函数

function davsele(sval)
{

var result = "<?php proCall();?>";
alert(result);
return false;
}
php jquery wordpress curl php-curl
1个回答
0
投票

你正在以某种方式混合Javascript和PHP,这是行不通的。您尝试在PHP函数中访问JS-Variable(sval),它不起作用。

您需要使用AJAX-Request调用服务器上的PHP函数,并将JS-Variable作为GET参数传递。

因此,您应该将PHP代码放在一个文件中(例如api.php)并在JS-Function中调用它:

function davsele(sval) {
  var xhttp = new XMLHttpRequest();
  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      alert(this.responseText);
    }
  };
  xhttp.open("GET", "api.php?value=" + sval, true);
  xhttp.send();
}

api.php的内容可能如下所示:

<?php
    $curl = curl_init();

    curl_setopt($curl, CURLOPT_URL, 'https://products-export-api.g2a.com/v1/products?page=' . $_GET['value']);
    curl_setopt($curl, CURLOPT_POST, 1);
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);

    $server_output = curl_exec($curl);

    //Gets the API data
    $response = curl_exec($curl);
    $err = curl_error($curl);
    //curl_close($curl);
    $dataget = json_decode($response,true);
    print_r($dataget);
    echo "test";
    curl_close ($curl);
?>
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