每次打印 MIP 时删除字符串中的最后一个值

Question

#########################################

.text 
main: 
    # Prompt for the string to enter
        li $v0, 4 
        la $a0, prompt
    syscall 

        # Read the string. 
        li $v0, 8   
        la $a0, word
        lw $a1, inputSize 
        syscall
        la $t0, word #set it so that word is in t0
        li $t1, 0 #length of string
        jal string_length #find length of stirng and store it in string_length
        li $t2, 0 #counter for print_loop
        jal print_loop
        j end
string_length:
    lb $s0, ($t0) #set byte to be checked to s0
    bnez $s0, not_end_string_length #if not at end of string then return to start of loop
    jr $ra #return to main, or wherever function was called
not_end_string_length: 
    addiu $t0, $t0, 1 #increment pointer    
    addiu $t1, $t1, 1 #add 1 to counter with length of string
    j string_length #go back to string_length
print_loop:  #print out for the amount of times that is the length of word entered  
    la $t0, word #put word in t0
    li $t3, 0 #counter for inner loop
    addi $t4, $1, -1 #set length of string to be printed to be one less than previous length printed
    # print out a new line  (formatting)
    li $v0, 4
    la $a0, newLine 
    syscall
    #works until here
        blt $t2, $t1, print_out #if counter is less than string length then print_out
        jr $ra #return to where called (end loop)
print_out:
    bge $t3, $t4, print_loop #go back to print loop if amount of character has reached amount that should be printed
    j not_end_print_out
not_end_print_out: ######################################## Errors are here 
    #print out char num t3#
    addi $t0, $t0, 1
    #set char to be value t3
    lb $a0, 0($t0)
    li $v0, 11
    syscall
    
    addi $t3, $t3, 1
    j print_out #go back to print_out
####################################################################
end:
    # Output end message
    li $v0,8
    la $a0, endMessage
    syscall
    #

.data
prompt: .asciiz "\nEnter a string: "
word: .space 31
char: .space 2
inputSize: .word 30
charSize: .word 1
newLine: .asciiz "\n"
endMessage: .asciiz "\nYou have reached the end. Goodbye"

我需要我的代码来打印用户输入的字符串，其中每次删除最后一个值。例如，如果输入“hi”则

嗨

h

将被打印出来。

我尝试用打印字符的代码更改一些内容，但老实说我真的不知道该怎么做。我尝试更改它，以便有几种不同的方法来打印内容，但什么也没有。由于某种原因，第一个字符没有被打印，然后只打印了一行。该行有一些垃圾值。

Answer 1

如果有人想知道我设法通过改变一些小错误来解决这个问题。事实证明，大多数问题都是小问题，比如写 $1 而不是 $t1。希望下次我写代码时我会多检查几次。