如何正确设置内部laravel网站消息数据库

Question

我正在努力设置我的消息传递数据库。我允许用户通过我的网站互相发送消息。当用户转到其消息面板时，我希望数据库返回这样的数据

1[
Message with sender_id = 1 and sent_to_id = 2 body = text here
Message with sender_id = 2 and sent_to_id = 1 body = text here
Message with sender_id = 1 and sent_to_id = 2 body = text here
]
2[
Message with sender_id = 1 and sent_to_id = 4 body = text here
Message with sender_id = 4 and sent_to_id = 1 body = text here
]
3[
Message with sender_id = 16 and sent_to_id = 1 body = text here
Message with sender_id = 1 and sent_to_id = 16 body = text here
]

我开始这样创建数据库

$table->bigIncrements('id');
            $table->unsignedBigInteger('sender_id');
            $table->unsignedBigInteger('sent_to_id');
            $table->text('body');
            $table->timestamps(); 
            $table->foreign('sender_id')
                    ->references('id')->on('users')
                    ->onDelete('cascade');
            $table->foreign('sent_to_id')
                    ->references('id')->on('users')
                    ->onDelete('cascade');

然后使用我的用户模型

public function received()
    {
        return $this->hasMany(Message::class, 'sent_to_id');
    }
 public function sent()
    {
        return $this->hasMany(Message::class, 'sender_id');
    }

效果很好，但我看不到像第一个示例那样将消息分组为用户之间的对话的方法。

1. 我是否为要达到的目的正确设置了数据库？

2. 我将如何在模型中进行设置以返回按用户之间的对话分组的消息？

Answer 1

您可以使用conversations和sender_id创建一个recipient_id表以及一个单独的messages表来存储属于该会话的消息。

/** Conversations **/
class Conversation extends Model
{

    protected $fillable = ['sender_id', 'sent_to_id'];

    public function messages()
    {
        return $this->hasMany(Message::class);
    }
    ...

/** Messages **/
class Message extends Conversation
{
    protected $fillable = [
        'user_id',// User that created this message
        'message', // Body of the message
        'conversation_id'
    ];

    public function conversation()
    {
        return $this->belongsTo(Conversation::class);
    }
    ...

通过以上设置，您可以与消息进行对话：

/** Currently authenticated user **/
$userId = auth()->id();
$conversations = App\Conversation::where('sender_id', $userId)
    ->orWhere('sent_to_id', $userId)
    ->with('messages')->get();

Answer 2

您可以创建包含以下内容的消息表：

• sender_id int
• receiver_id int
• body varchar（255）
• 日期创建时间
• seen_at datetime nullable

    /** Messages **/
    class Message extends Model
    {
        protected $fillable = [
            'sender_id',
            'receiver_id',
            'body',
            'seen_at',
        ];
    }

并使用：]进行检索

// don't  forget to update seen attribute while fetching
App\Message::where('receiver_id',$userId)->update(['seen_at' => date('Y-m-d H:i:s') ]);
//
$userId = auth::user()->id(); // authenticated_user
$messages = App\Message::where('sender_id', $userId)->orWhere('receiver_id',$userId)->get();
并且您可以轻松地对其进行映射以对其进行样式设置（在视图上）

@foreach($messages as $message)
  @if ($message->sender_id == Auth::user()->id)
    <p class='message_sent'> {{$message->body}} </p>
  @else
    <p class='message_received'> {{$message->body}} </p>
  @endif
 @if ($message->seen_at)
  <p> {{$message->seen_at}} </p>
 @endif
@endforeach