在 Supabase 上运行 SUM(*)

Question

我从 Supabase 开始，想了解如何在

SUM()

中传递

SELECT

聚合器。

我注意到对于

COUNT

，我们使用：

const { data, error, range, count } = supabase
  .from('table')
  .select('*', { count: 'exact' })

还有什么类似

SUM

我没注意到的吗？

我的查询是这样的：

select
  "GE_PRODUCTS",
  sum("GE_QUANTITY") as Quantity,
  sum("GE_SALEVALUE") as Revenue
from "GE_SELLS"
where "GE_ENTERPRISE" = 'G.E.'
  and "DELETED" <> '*'
group by "GE_PRODUCTS"
order by Revenue desc
limit 3;

Answer 1

您最好的选择是将其放入 PostgreSQL 函数中并使用 .rpc()从 Supabase

调用它：

Answer 2

CREATE OR REPLACE FUNCTION get_my_sums() 
    RETURNS TABLE (
        "GE_PRODUCTS" TEXT,
        Quantity NUMBER,
        Revenue NUMBER
) AS $$
DECLARE 
    var_r record;
BEGIN
    RETURN QUERY 
    select
    "GE_PRODUCTS",
    sum("GE_QUANTITY") as Quantity,
    sum("GE_SALEVALUE") as Revenue
    from "GE_SELLS"
    where "GE_ENTERPRISE" = 'G.E.'
    and "DELETED" <> '*'
    group by "GE_PRODUCTS"
    order by Revenue desc
    limit 3;
END; $$ 
LANGUAGE 'plpgsql';

Answer 3

PostgREST v12 现在支持 Supabase Javascript SDK 的聚合函数:

const { data, error, range, count } = supabase
  .from('GE_SELLS')
  .select(
    'GE_PRODUCTS, GE_QUANTITY.sum(), GE_SALEVALUE.sum()', 
    { count: 'exact' }
  )
  .eq('GE_ENTERPRISE', 'G.E.')
  .not('DELETED', 'eq', '*')
  .group('GE_PRODUCTS')
  .order('Revenue', { ascending: false })
  .limit(3)