我正在使用 Python 3.10 进行编码，并且使用 PyCharm 社区版 2021.2.2 进行编码。 我想知道Python中是否有一种方法可以编码连接4（我已经编码了放置的计数器和所有内容），然后还使用某种公式来检查是否有4个连续。为了检查到目前为止是否有 4 个连续的计数器，我只能想到手动检查并输入连续 4 个可能的组合，无论是对角线、垂直、水平还是其他。正如我所说，有没有一种简单的方法可以做到这一点，而无需手动输入所有获胜组合？
我还没有手动尝试过，因为我希望能得到一些关于如何不手动执行此操作的帮助。 这是我到目前为止的代码：
import turtle
import mouse
from tkinter import *
#turtles
redturtle = turtle.Turtle()
blueturtle = turtle.Turtle()
boredturtle = turtle.Turtle()
#column values- positions
column1 = [380, 164, 476, 860]
column2 = [488, 164, 575, 860]
column3 = [587, 164, 678, 860]
column4 = [684, 164, 779, 860]
column5 = [783, 164, 875, 860]
column6 = [884, 164, 976, 860]
column7 = [983, 164, 1078, 860]
#connect 4 board values - where a placement is for background and to checkwin
col7 = [1,2,3,4,5,6]
col6 = [1,2,3,4,5,6]
col5 = [1,2,3,4,5,6]
col4 = [1,2,3,4,5,6]
col3 = [1,2,3,4,5,6]
col2 = [1,2,3,4,5,6]
col1 = [1,2,3,4,5,6]
#square values- 1 is bottom left corner
x1 = -305
x2 = -200
x3 = -100
x4 = 0
x5 = 100
x6 = 200
x7 = 300
listy = [-290, -170, -50, 70, 190, 300]
y1 = -290
y2 = -170
y3 = -50
y4 = 70
y5 = 190
y6 = 300
#column counters - to check what "Y" to put it at
count1 = [0]
count2 = [0]
count3 = [0]
count4 = [0]
count5 = [0]
count6 = [0]
count7 = [0]
def drawboard():
boredturtle.hideturtle()
boredturtle.speed(0)
boredturtle.pensize(15)
boredturtle.penup()
#sideways
boredturtle.setposition(-1000, -350)
boredturtle.pendown()
boredturtle.setposition(1000, -350)
boredturtle.penup()
boredturtle.setposition(-1000, -230)
boredturtle.pendown()
boredturtle.setposition(1000, -230)
boredturtle.penup()
boredturtle.setposition(-1000, -110)
boredturtle.pendown()
boredturtle.setposition(1000, -110)
boredturtle.penup()
boredturtle.setposition(-1000, 10)
boredturtle.pendown()
boredturtle.setposition(1000, 10)
boredturtle.penup()
boredturtle.setposition(-1000, 130)
boredturtle.pendown()
boredturtle.setposition(1000, 130)
boredturtle.penup()
boredturtle.setposition(-1000, 250)
boredturtle.pendown()
boredturtle.setposition(1000, 250)
#top
boredturtle.penup()
boredturtle.setposition(-1000, 350)
boredturtle.pendown()
boredturtle.setposition(1000, 350)
#downwards
boredturtle.penup()
boredturtle.setposition(-360, 1000)
boredturtle.pendown()
boredturtle.setposition(-360, -1000)
boredturtle.penup()
boredturtle.setposition(350, 1000)
boredturtle.pendown()
boredturtle.setposition(350, -1000)
boredturtle.penup()
boredturtle.setposition(-250, 1000)
boredturtle.pendown()
boredturtle.setposition(-250, -1000)
boredturtle.penup()
boredturtle.setposition(-150, 1000)
boredturtle.pendown()
boredturtle.setposition(-150, -1000)
boredturtle.penup()
boredturtle.setposition(-50, 1000)
boredturtle.pendown()
boredturtle.setposition(-50, -1000)
boredturtle.penup()
boredturtle.setposition(50, 1000)
boredturtle.pendown()
boredturtle.setposition(50, -1000)
boredturtle.penup()
boredturtle.setposition(150, 1000)
boredturtle.pendown()
boredturtle.setposition(150, -1000)
boredturtle.penup()
boredturtle.setposition(250, 1000)
boredturtle.pendown()
boredturtle.setposition(250, -1000)
boredturtle.penup()
boredturtle.setposition(350, 1000)
boredturtle.pendown()
boredturtle.setposition(350, -1000)
drawboard()
whoseturn = [0]
def redcounterplace(x, y, count):
redturtle.speed(0)
redturtle.hideturtle()
redturtle.color("red")
redturtle.pensize(80)
redturtle.penup()
listofy = y
valy = listofy[count]
redturtle.setposition(x,valy)
redturtle.pendown()
redturtle.circle(1)
def bluecounterplace(x,y, count):
blueturtle.speed(0)
blueturtle.hideturtle()
blueturtle.color("blue")
blueturtle.pensize(80)
blueturtle.penup()
listofy = y
valy = listofy[count]
blueturtle.setposition(x, valy)
blueturtle.pendown()
blueturtle.circle(1)
def columnchecker():
mousepos = mouse.get_position()
if mousepos[0] >= column1[0] and mousepos[0] <= column1[2] and mousepos[1] >= column1[1] and mousepos[1] <= column1[3]:
return ("y1")
if mousepos[0] >= column2[0] and mousepos[0] <= column2[2] and mousepos[1] >= column2[1] and mousepos[1] <= column2[3]:
return ("y2")
if mousepos[0] >= column3[0] and mousepos[0] <= column3[2] and mousepos[1] >= column3[1] and mousepos[1] <= column3[3]:
return ("y3")
if mousepos[0] >= column4[0] and mousepos[0] <= column4[2] and mousepos[1] >= column4[1] and mousepos[1] <= column4[3]:
return ("y4")
if mousepos[0] >= column5[0] and mousepos[0] <= column5[2] and mousepos[1] >= column5[1] and mousepos[1] <= column5[3]:
return ("y5")
if mousepos[0] >= column6[0] and mousepos[0] <= column6[2] and mousepos[1] >= column6[1] and mousepos[1] <= column6[3]:
return ("y6")
if mousepos[0] >= column7[0] and mousepos[0] <= column7[2] and mousepos[1] >= column7[1] and mousepos[1] <= column7[3]:
return ("y7")
def putinbackgroundcheck(person, columnnum, count):
if person == 1:
if columnnum == "y1":
col1[count] = "b"
if columnnum == "y2":
col2[count] = "b"
if columnnum == "y3":
col3[count] = "b"
if columnnum == "y4":
col4[count] = "b"
if columnnum == "y5":
col5[count] = "b"
if columnnum == "y6":
col6[count] = "b"
if columnnum == "y7":
col7[count] = "b"
if person == 0:
if columnnum == "y1":
col1[count] = "r"
if columnnum == "y2":
col2[count] = "r"
if columnnum == "y3":
col3[count] = "r"
if columnnum == "y4":
col4[count] = "r"
if columnnum == "y5":
col5[count] = "r"
if columnnum == "y6":
col6[count] = "r"
if columnnum == "y7":
col7[count] = "r"
def main():
if columnchecker() == "y1" and whoseturn[0] == 0:
redcounterplace(x1, listy, count1[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count1[0])
count1[0] = count1[0] + 1
whoseturn[0] = 1
elif columnchecker() == "y2" and whoseturn[0] == 0:
redcounterplace(x2, listy, count2[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count2[0])
count2[0] = count2[0] + 1
whoseturn[0] = 1
elif columnchecker() == "y3" and whoseturn[0] == 0:
redcounterplace(x3, listy, count3[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count3[0])
count3[0] = count3[0] + 1
whoseturn[0] = 1
elif columnchecker() == "y4" and whoseturn[0] == 0:
redcounterplace(x4, listy, count4[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count4[0])
count4[0] = count4[0] + 1
whoseturn[0] = 1
elif columnchecker() == "y5" and whoseturn[0] == 0:
redcounterplace(x5, listy, count5[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count5[0])
count5[0] = count5[0] + 1
whoseturn[0] = 1
elif columnchecker() == "y6" and whoseturn[0] == 0:
redcounterplace(x6, listy, count6[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count6[0])
count6[0] = count6[0] + 1
whoseturn[0] = 1
elif columnchecker() == "y7" and whoseturn[0] == 0:
redcounterplace(x7, listy, count7[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count7[0])
count7[0] = count7[0] + 1
whoseturn[0] = 1
elif columnchecker() == "y1" and whoseturn[0] == 1:
bluecounterplace(x1, listy, count1[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count1[0])
count1[0] = count1[0] + 1
whoseturn[0] = 0
elif columnchecker() == "y2" and whoseturn[0] == 1:
bluecounterplace(x2, listy, count2[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count2[0])
count2[0] = count2[0] + 1
whoseturn[0] = 0
elif columnchecker() == "y3" and whoseturn[0] == 1:
bluecounterplace(x3, listy, count3[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count3[0])
count3[0] = count3[0] + 1
whoseturn[0] = 0
elif columnchecker() == "y4" and whoseturn[0] == 1:
bluecounterplace(x4, listy, count4[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count4[0])
count4[0] = count4[0] + 1
whoseturn[0] = 0
elif columnchecker() == "y5" and whoseturn[0] == 1:
bluecounterplace(x5, listy, count5[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count5[0])
count5[0] = count5[0] + 1
whoseturn[0] = 0
elif columnchecker() == "y6" and whoseturn[0] == 1:
bluecounterplace(x6, listy, count6[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count6[0])
count6[0] = count6[0] + 1
whoseturn[0] = 0
elif columnchecker() == "y7" and whoseturn[0] == 1:
bluecounterplace(x7, listy, count7[0])
putinbackgroundcheck(whoseturn[0], columnchecker(), count7[0])
count7[0] = count7[0] + 1
whoseturn[0] = 0
def checkwin():
mouse.on_click(lambda: main())
turtle.done()
您应该使用列表的列表而不是单个变量来表示和操作棋盘。将游戏逻辑与演示分离也会更容易。这将允许您全面测试图形 UI 之外的逻辑。
将棋盘表示为列列表，每个列都是棋盘单元格内容的列表（包含“.”、“X”或“O”），您的最终游戏检查可以使用嵌套循环来提取 4 单元格每个 4x4 子块的线：
def winOrDraw(board):
xo = "" # 4-cell segments as a string
for c in range(len(board)-3): # top corner of each 4x4 blocks
for r in range(len(board[0])-3):
xo += "|"+"".join(board[c][r+i] for i in range(4)) # vertical
xo += "|"+"".join(board[c+i][r] for i in range(4)) # horiz.
xo += "|"+"".join(board[c+i][r+i] for i in range(4)) # diag 1
xo += "|"+"".join(board[c+3-i][r+i] for i in range(4)) # diag 2
if "XXXX" in xo: return "X"
if "OOOO" in xo: return "O"
if "." not in xo: return "DRAW"
return None
然后可以在没有图形 UI 的情况下执行这些操作，一旦你让它工作，UI 只需要显示面板的内容并接受用户输入。
基于文本的测试：
# setup
cols = 7
rows = 6
board = [ ["."]*rows for _ in range(cols) ]
player = "X"
while not winOrDraw(board): # loop until end of game
# display board
print(*range(1,cols+1))
for r in reversed(range(rows)):
print(*(board[c][r] for c in range(cols)))
# get and validate user input
col = input(f"player {player} select column (1-{cols}): ")
if col not in map(str,range(1,cols)):
print("invalid column number")
continue
col = int(col)
if not "." in board[col]:
print("column already full")
continue
# perform move
row = board[col].index(".")
board[col][row] = player
# switch player
player = "X" if player == "O" else "O"
print("GAME OVER. WINNER IS ",winOrDraw(board))