我有以下文件(test.txt),我想更改逻辑如下:
0 becomes 1
1 becomes 2
2 becomes 3
3 becomes 4
4 becomes 5
5 becomes 6
6 becomes 7
7 becomes 8
8 becomes 9
9 becomes 0
$ cat test.txt
69|1074330570|1,sip:+121345633210x3Bverstat=TN-Validation-Passed|tel:+12134565534|0
69|1077822111|2,;tel:+12223120011~sip:[email protected];|sip:[email protected]|0
我想更改最后 4 位数字,但当 x 紧邻 0x 时,则 0 不算数。 例如: 在第一行“+121345633210x”中,后 4 位是 3321。 在第二行中,'+12223120011',最后4位是0011和'+12223120051',最后4位是0051 输出应如下所示:
69|1074330570|1,sip:+121345644320x3Bverstat=TN-Validation-Passed|tel:+12134566645|0
69|1077822111|2,;tel:+12223121122~sip:[email protected];|sip:[email protected]|0
它需要排除“+1”,然后计算“10”位数字,其中我想替换第三列和第四列中的最后 4 位。
121345633210 becomes 121345644320 / 12134565534 becomes 12134566645
12223120011 becomes 12223121122 / 12223120051 becomes 12223121162 / 13123120022 becomes 13123121133
当列只是一个数字时,我使用了以下逻辑。但在这种情况下,它还有其他内容,因此下面的逻辑不起作用,但通过添加 1 位数字来转换数字是正确的。
awk -F"|" -v OFS="|" '
NR>0 {
for (i=3;i<=4;i++) {
str = substr($i, 1, length($i) - 4)
for (j = length($i) - 3; j <= length($i); j++) {
str = str (substr($i, j, 1) + 1) % 10
}
$i = str
}
}
1'
使用
gnu-awk
,您可以执行以下操作:
awk '
function rep(s, i, r, ch) {
for (i=1; i<=length(s); ++i) {
ch = substr(s,i,1)
r = r (ch == 9 ? 0 : ch+1)
}
return r
}
n = split($0, pn, /\+/) {
for (j=2; j<=n; ++j) {
if (match(pn[j], /([0-9]+)([0-9]{4})(0x)?(.*)/, a))
pn[j] = a[1] rep(a[2]) a[3] a[4]
}
$0 = pn[1]
for (j=2; j<=n; ++j)
$0 = $0 "+" pn[j]
} 1' file
69|1074330570|1,sip:+121345634321x3Bverstat=TN-Validation-Passed|tel:+12134566645|0
67|1077822111|2,;tel:+12223121122~sip:[email protected];|sip:[email protected]|0