我该如何去约的范围内产生随机数?
你可以试试
Random r = new Random();
int rInt = r.Next(0, 100); //for ints
int range = 100;
double rDouble = r.NextDouble()* range; //for doubles
看一下
Random Class,Random.Next Method (Int32, Int32)和Random.NextDouble Method
试试下面的代码。
Random rnd = new Random();
int month = rnd.Next(1, 13); // creates a number between 1 and 12
int dice = rnd.Next(1, 7); // creates a number between 1 and 6
int card = rnd.Next(52); // creates a number between 0 and 51
就像是:
var rnd = new Random(DateTime.Now.Millisecond);
int ticks = rnd.Next(0, 3000);
采用:
Random r = new Random();
int x= r.Next(10);//Max range
对于未来的读者,如果你想在一个范围内的随机数使用下面的代码:
public double GetRandomNumberInRange(double minNumber, double maxNumber)
{
return new Random().NextDouble() * (maxNumber - minNumber) + minNumber;
}
下面是从Darrelk answer更新版本。它是利用C# extension methods实现。它不分配内存(新的随机())每次调用此方法。
public static class RandomExtensionMethods
{
public static double NextDoubleRange(this System.Random random, double minNumber, double maxNumber)
{
return random.NextDouble() * (maxNumber - minNumber) + minNumber;
}
}
用法(确保导入包含RandomExtensionMethods类的命名空间):
var random = new System.Random();
double rx = random.NextDoubleRange(0.0, 1.0);
double ry = random.NextDoubleRange(0.0f, 1.0f);
double vx = random.NextDoubleRange(-0.005f, 0.005f);
double vy = random.NextDoubleRange(-0.005f, 0.005f);