如何使用JPA管理多个实体?

问题描述 投票:0回答:2

上下文

我正在尝试创建一个简单的API来学习Spring Boot和JPA。信息存储在H2数据库中。

我有2个实体:missionuser

几个用户被分配到一个任务。用户可以分配到不同的任务。

所以,我的班级Mission有一个属性private ArrayList<User> users;

目的

我的目标是创建一些请求:

  • (获取请求)IP/missions/123456/users:获取分配给任务123456的所有用户
  • (PUT请求)IP/missions/456789:分配给456789任务的用户

所以,绑定两个实体。

问题

但我不知道如何存储/绑定相对于missionuser的信息。好的方法是用方案Assignements(id_user, id_mission)创建一个“关联表”?

感谢帮助!

编辑1:代码

实体使命

@Entity
public class Mission{

    @Id
    private String id;
    private String name;
    private Date start;
    private Date end;
    private ArrayList<User> users;
    private int status;

    public Mission() {
    }

    public Mission(String name, Date start, Date end) {
        this.name = name;
        this.start = start;
        this.end = end;
        this.status = 0;
    }

    // getters and setters
}

实体用户

@Entity
public class User {

    @Id
    private String id;
    private String name;

    public User() {
    }

    public User(String name) {
        this.name = name;
    }

    // getters and setters
}

SQL

我使用SQL脚本。目前,脚本看起来像:

INSERT INTO mission (id, name, start, end, status) VALUES ('de7d9052-4961-4b4f-938a-3cd12cbe1f82', 'mission 1', '2019-02-11', '2019-02-13', 0)
INSERT INTO mission (id, name, start, end, status) VALUES ('425e7701-02c6-4de3-9333-a2459eece1c8', 'mission 2', '2019-02-10', '2019-02-15', 0)

编辑2:新代码(使用@ManyToMany)

实体

@Entity
public class Mission {

    @Id
    private String missionid;
    private String namemission;
    private Date start;
    private Date end;
    @ManyToMany
    @JoinTable(name = "mission_user",
        joinColumns = @JoinColumn(name = "missionid"),
        inverseJoinColumns = @JoinColumn(name = "userid")
    )
    private Set<User> users = new HashSet<>();
    private int status;

    public Mission() {}

    public Mission(String name, Date start, Date end) {
        this.namemission = name;
        this.start = start;
        this.end = end;
        this.status = 0;
    }
}

@Entity
public class User {

    @Id
    private String iduser;
    private String nomuser;
    @ManyToMany(mappedBy = "users")
    private Set<Mission> missions = new HashSet<>();

    public User() {}

    public User(String nom) {
        this.nomuser = nom;
    }

}

@RepositoryRestResource(collectionResourceRel = "mission")
public interface MissionResource extends JpaRepository<Mission, String> {
    ...
}

@RepositoryRestResource(collectionResourceRel = "user")
public interface UserResource extends JpaRepository<User, String> {
    ...
}

休息控制器

@RestController
@RequestMapping(value = "/missions", produces = MediaType.APPLICATION_JSON_VALUE)
@ExposesResourceFor(Mission.class)
public class MissionRepresentation {
    private final MissionResource missionResource;
    private final UserResource userResource;

    public MissionRepresentation(MissionResource missionResource, UserResource userResource) {
        this.missionResource = missionResource;
        this.userResource = userResource;
    }

    // mapping
}
java spring spring-boot jpa spring-hateoas
2个回答
1
投票

最好的方法是实现一个连接表,就像你说的那样。这将是这样的:

create table mission_user (
    mission_id int,
    user_id int,
    primary key (mission_id, user_id)
)

然后使用这张表作为@ManyToMany的映射或实体的MissionUser,并将UserMission映射为@OneToMany


1
投票

任务类将具有:

@Entity
public class Mission {
...
    @ManyToMany(mappedBy = "missions")
    private List<User> users;
...
}

和用户类将具有:

@Entity
public class User {
...

    @ManyToMany(mappedBy = "users")
    private List<Mission> missions;
...
}

这将在您的数据库中创建一个表,其名称类似于:mission_uesrs,它将具有missionId和userId作为唯一列。

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