正如您在图片中看到的,当人们使用地图时会生成一个圆锥体。我想知道是否有可能检测到锥体like this的两个外线,但最终目标是使用这些信息来找到线条所处的角度。
我跟随this tutorial on hough-transform但最终得到了this。寻找一种更容易找到角度的方法。
import numpy as np
from skimage.transform import hough_line
from scipy import misc
import matplotlib.pyplot as plt
from matplotlib import cm
image = misc.imread("cone.jpg", flatten=True)
# Classic straight-line Hough transform
h, theta, d = hough_line(image)
# Generating figure 1
fig, axes = plt.subplots(1, 3, figsize=(9, 3),
subplot_kw={'adjustable': 'box-forced'})
ax = axes.ravel()
ax[0].imshow(image, cmap=cm.gray)
ax[0].set_title('Input image')
ax[0].set_axis_off()
ax[1].imshow(np.log(1 + h),
extent=[np.rad2deg(theta[-1]), np.rad2deg(theta[0]), d[-1], d[0]],
cmap=cm.gray, aspect=1/1.5)
ax[1].set_title('Hough transform')
ax[1].set_xlabel('Angles (degrees)')
ax[1].set_ylabel('Distance (pixels)')
ax[1].axis('image')
ax[2].imshow(image, cmap=cm.gray)
for _, angle, dist in zip(*hough_line_peaks(h, theta, d)):
y0 = (dist - 0 * np.cos(angle)) / np.sin(angle)
y1 = (dist - image.shape[1] * np.cos(angle)) / np.sin(angle)
ax[2].plot((0, image.shape[1]), (y0, y1), '-r')
ax[2].set_xlim((0, image.shape[1]))
ax[2].set_ylim((image.shape[0], 0))
ax[2].set_axis_off()
ax[2].set_title('Detected lines')
plt.tight_layout()
plt.show()