有排序在一个对象数组的数组更有效的方法?

问题描述 投票:0回答:2

对于下面的阵列对象的事结构:

Events : {
    events : [
        {
          startDTG : {day: 0, month: 0, year: 0, time: "" },
          endDTG : {day: 0, month: 0, year: 0, time: "" },
          mode: ""
        },
        ...
    ],
    blah...,
    blah...,
    blah...
}

我在努力寻找一种更有效的方式基础上,events键(日期 - 时间组)的startDTG对象进行排序。目前我使用下面,但我觉得必须有一个更好的方式来做到这一点!

SortEvents: function() {
    this.Events.events.sort(function(a, b){return a.startDTG.time - b.startDTG.time});
    this.Events.events.sort(function(a, b){return a.startDTG.day - b.startDTG.day});
    this.Events.events.sort(function(a, b){return a.startDTG.month - b.startDTG.month});
    this.Events.events.sort(function(a, b){return a.startDTG.year - b.startDTG.year});
},

编辑1:愿望是通过Year > Month > Day > Time进行排序

我在其中我在效率的需要它的名字放弃这一习俗DTG一个临界点。我可以张贴整个代码,如果提出要求,但可能没有,因为它是JS写了一个名为“Medialon的”专有控制系统内工作总感

编辑2:添加了快速制造JSON下面的代码转储,以协助结构的可读性。忽略了一个事实,他们都是“字符串”这是多么的Medialon为stringifies持久

{
  "events": [
    {
      "startDTG": {
        "day": "8",
        "month": "2",
        "year": "2019",
        "time": "06:35",
        "dayName": "5"
      },
      "endDTG": {
        "day": "9",
        "month": "2",
        "year": "2019",
        "time": "08:35",
        "dayName": "6"
      },
      "mode": "1"
    },
    {
      "startDTG": {
        "day": "27",
        "month": "2",
        "year": "2019",
        "time": "17:35",
        "dayName": "3"
      },
      "endDTG": {
        "day": "28",
        "month": "2",
        "year": "2019",
        "time": "06:35",
        "dayName": "4"
      },
      "mode": "1"
    },
    {
      "startDTG": {
        "day": "1",
        "month": "2",
        "year": "2019",
        "time": "14:35",
        "dayName": "5"
      },
      "endDTG": {
        "day": "2",
        "month": "2",
        "year": "2019",
        "time": "12:35",
        "dayName": "6"
      },
      "mode": "1"
    }
  ],
javascript arrays sorting object controls
2个回答
1
投票

我还是不太清楚你的数据结构,但这样的事情应该是接近:

const events = [
  {name: 'a', startDTG: {year: 2019, month: 1,  day: 4,  time: '14:21:46'}, endDTG: ''},
  {name: 'b', startDTG: {year: 2018, month: 10, day: 7,  time: '12:13:59'}, endDTG: ''},
  {name: 'c', startDTG: {year: 2019, month: 1,  day: 4,  time: '09:23:51'}, endDTG: ''},
  {name: 'd', startDTG: {year: 2019, month: 1,  day: 2,  time: '15:02:36'}, endDTG: ''},
  {name: 'e', startDTG: {year: 2017, month: 9,  day: 17, time: '03:25:29'}, endDTG: ''},
  {name: 'f', startDTG: {year: 2017, month: 9,  day: 17, time: '03:25:28'}, endDTG: ''},
  {name: 'g', startDTG: {year: 2018, month: 4,  day: 14, time: '11:07:42'}, endDTG: ''},
]

events.sort((
  {startDTG: {year: y1, month: m1, day: d1, time: t1}}, 
  {startDTG: {year: y2, month: m2, day: d2, time: t2}}
) => 
  // y1 - y2 || m1 - m2 || d1 - d2 || (t1 < t2 ? -1 : t1 > t2 ? 1 : 0)           
  y1 - y2 || m1 - m2 || d1 - d2 || t1.localeCompare(t2)
)

console.log(events)

1
投票

另一种解决方案可以将数据映射到Date(),然后比较getTime()返回的毫秒。

let data = {
  "events": [
    {
      "startDTG": {"day": "8", "month": "2", "year": "2019", "time": "6:35", "dayName": "5"},
      "endDTG": {"day": "9", "month": "2", "year": "2019", "time": "6:35", "dayName": "6"},
      "mode": "1"
    },
    {
      "startDTG": {"day": "27", "month": "2", "year": "2019", "time": "6:35", "dayName": "3"},
      "endDTG": {"day": "28", "month": "2", "year": "2019", "time": "6:35", "dayName": "4"},
      "mode": "1"
    },
    {
      "startDTG": {"day": "1", "month": "2", "year": "2019", "time": "6:35", "dayName": "5"},
      "endDTG": {"day": "2", "month": "2", "year": "2019", "time": "6:35", "dayName": "6"},
      "mode": "1"
    }
  ]
};

const startDTGToStr = o => `${o.year}-${o.month}-${o.day} ${o.time}`

data.events.sort((a, b) =>
{
    a = new Date(startDTGToStr(a.startDTG));
    b = new Date(startDTGToStr(b.startDTG));
    return a.getTime() - b.getTime();
});

console.log(data.events);
© www.soinside.com 2019 - 2024. All rights reserved.