感谢@Leo Dabus,我现在有这个Extension
。它适用于单个String
,但我如何将这个相同的逻辑实现为Set
的Strings
,如var mySet = ["word", "notaword", "stillnotaword"]
。在这个例子中,我希望该函数仅将第一个index
识别为true
(即英语单词)。
extension String {
public mutating func isEnglishWord() -> Bool {
return UITextChecker().rangeOfMisspelledWord(in: self, range: NSRange(location: 0, length: utf16.count), startingAt: 0, wrap: false, language: "en_US").location == NSNotFound
}
}
var myString = "word"
myString.isEnglishWord()
let words = ["word", "notaword", "stillnotaword"]
let validWords = words.filter { word -> Bool in
return word.isEnglishWord()
}
let wordsArray : NSArray = NSArray(array: words)
let validWordsIndexes = wordsArray.indexesOfObjects { (word, index, _) -> Bool in
return (word as! String).isEnglishWord()
}
print(validWords)
print(validWordsIndexes)
extension String {
public func isEnglishWord() -> Bool {
return UITextChecker().rangeOfMisspelledWord(in: self, range: NSRange(location: 0, length: utf16.count), startingAt: 0, wrap: false, language: "en_US").location == NSNotFound
}
}
我添加了代码来打印有效单词和有效单词的索引。您可以选择适合您的选择。谢谢