如何在Azure函数（v2）中的Pascal Case中返回JSON？

Question

我有这个功能

[FunctionName("json")]
public static JsonResult json
(
        [HttpTrigger(AuthorizationLevel.Anonymous, new string[] { "POST", "GET", "DELETE", "PATCH", "PUT" })]
        HttpRequest req,
        TraceWriter log
)
{
    return new JsonResult(new
    {
        Nome = "TONY",
        Metodo = req.Method.ToString()
    });
}

问题是它正在回归

{"nome":"TONY","metodo":"GET"}

我想要它回来

{"Nome":"TONY","Metodo":"GET"}

在ASP.Net Core 2中我使用了这个：

services.AddMvc()
            .AddJsonOptions(options => options.SerializerSettings.ContractResolver = new Newtonsoft.Json.Serialization.DefaultContractResolver());
// Keep the Case as is

如何配置Azure功能以这种方式？

Answer 1

你可以这样做：

[FunctionName("json")]
    public static HttpResponseMessage Run(
        [HttpTrigger(AuthorizationLevel.Function, "get", Route = null)]HttpRequestMessage req, TraceWriter log)
    {
        return new HttpResponseMessage(HttpStatusCode.OK)
        {
            RequestMessage = req,
            Content = new StringContent(
                content: JsonConvert.SerializeObject(new
                {
                    Nome = "TONY",
                    Metodo = req.Method.ToString()
                }),
                encoding: System.Text.Encoding.UTF8,
                mediaType: "application/json")
        };
    }

Answer 2

将JsonPropertyAttribute添加到属性中，并通过文件顶部的#r“Newtonsoft.Json”包含Json.NET。

#r "Newtonsoft.Json"

using Newtonsoft.Json;

并装饰属性

[JsonProperty(PropertyName = "nome" )]
public string Nome { get; set; }

[JsonProperty(PropertyName = "metodo" )]
public string Metodo { get; set; }