在同一类科特林@Provides和@Binds方法

问题描述 投票:7回答:1

匕首2.11之后,我们可以用一个@Binds注释和标记我们的模块为抽象在这种情况下,这是比具体更有效。

如果我的模块有两种@Provides和@Binds方法,我有两个选择:

  1. 最简单的将是纪念你@Provides实例方法为静态。
  2. 如果有必要将其作为保持实例方法,那么您可以将模块拆分为两个,并提取出所有的@Binds方法为抽象的模块。

第二个选项工作正常,在Java和科特林但第一个选项在Java中工作正常,但我不知道如何实现在科特林相同。如果我移动@Provides方法伴侣反对它扔Error:(30, 1) error: @Provides methods can only be present within a @Module or @ProducerModule。在科特林如何才能做到这一点。

第二个选项:(工作)

ApplicationModule.kt

@Module(includes = [ApplicationModule.Declarations::class])
abstract class ApplicationModule {
    @Module
    internal interface Declarations {
        @Binds
        fun bindContext(application: Application): Context
    }

    @Provides
    @Singleton
    fun provideMvpStarterService(): MvpStarterService {
        return MvpStarterServiceFactory.makeStarterService()
    }
}

第一个选项:(不工作)

ApplicationModule.kt

@Module
abstract class ApplicationModule {
    //expose Application as an injectable context
    @Binds
    internal abstract fun bindContext(application: Application): Context

    companion object {
        @JvmStatic
        @Provides
        @Singleton
        fun provideMvpStarterService(): MvpStarterService {
            return MvpStarterServiceFactory.makeStarterService()
        }
    }
}

对于第一种选择生成的Java文件:

@kotlin.Metadata(mv = {1, 1, 9}, bv = {1, 0, 2}, k = 1, d1 = {"\u0000\u001a\n\u0002\u0018\u0002\n\u0002\u0010\u0000\n\u0002\b\u0002\n\u0002\u0018\u0002\n\u0000\n\u0002\u0018\u0002\n\u0002\b\u0003\b\'\u0018\u0000 \b2\u00020\u0001:\u0001\bB\u0005\u00a2\u0006\u0002\u0010\u0002J\u0015\u0010\u0003\u001a\u00020\u00042\u0006\u0010\u0005\u001a\u00020\u0006H!\u00a2\u0006\u0002\b\u0007\u00a8\u0006\t"}, d2 = {"Lio/mywebsie/di/ApplicationModule;", "", "()V", "bindContext", "Landroid/content/Context;", "application", "Landroid/app/Application;", "bindContext$app_debug", "Companion", "app_debug"})
@dagger.Module()
public abstract class ApplicationModule {
    public static final io.mywebsie.di.ApplicationModule.Companion Companion = null;

    @org.jetbrains.annotations.NotNull()
    @dagger.Binds()
    public abstract android.content.Context bindContext$app_debug(@org.jetbrains.annotations.NotNull()
    android.app.Application application);

    public ApplicationModule() {
        super();
    }

    @org.jetbrains.annotations.NotNull()
    @javax.inject.Singleton()
    @dagger.Provides()
    public static final io.mywebsie.data.remote.MvpStarterService provideMvpStarterService() {
        return null;
    }

    @kotlin.Metadata(mv = {1, 1, 9}, bv = {1, 0, 2}, k = 1, d1 = {"\u0000\u0012\n\u0002\u0018\u0002\n\u0002\u0010\u0000\n\u0002\b\u0002\n\u0002\u0018\u0002\n\u0000\b\u0086\u0003\u0018\u00002\u00020\u0001B\u0007\b\u0002\u00a2\u0006\u0002\u0010\u0002J\b\u0010\u0003\u001a\u00020\u0004H\u0007\u00a8\u0006\u0005"}, d2 = {"Lio/mywebsie/di/ApplicationModule$Companion;", "", "()V", "provideMvpStarterService", "Lio/mywebsie/data/remote/MvpStarterService;", "app_debug"})
    public static final class Companion {

        @org.jetbrains.annotations.NotNull()
        @javax.inject.Singleton()
        @dagger.Provides()
        public final io.mywebsie.data.remote.MvpStarterService provideMvpStarterService() {
            return null;
        }

        private Companion() {
            super();
        }
    }
}

更新:

感谢@大卫Medenjak您在评论中提供的link使一切清楚我在两个途径来实现第一个选项。

更新的代码:

第一个选项:(工作)

ApplicationModule.kt

@Module(includes = [ApplicationModule.AModule::class])
abstract class ApplicationModule {

    @Binds
    abstract fun bindContext(application: Application): Context

    @Module
    object AModule {
        @JvmStatic
        @Provides
        @Singleton
        fun provideMvpStarterService(): MvpStarterService {
            return MvpStarterServiceFactory.makeStarterService()
        }
    }
}

要么

@Module
abstract class ApplicationModule {
    @Binds
    abstract fun bindContext(application: Application): Context

    @Module
    companion object {
        @Provides
        @Singleton
        fun provideMvpStarterService(): MvpStarterService {
            return MvpStarterServiceFactory.makeStarterService()
        }
    }
}

这两个工作得很好,但由于某种原因,第一个选项看起来并不吸引我,所以我更喜欢第二个选项。

kotlin dagger-2
1个回答
1
投票

下面是一个例子代码来演示如何使用BindsProvides单一Kotlin class注解的方法:

@Module
abstract class MessagesPresentationModule {

    @Module
    companion object {
        const val MESSAGES = 0x00

        @JvmStatic
        @Provides
        fun provideRecyclerAdapter(
            itemComparator: DisplayItemComperator,
            factoryMap: Map<Int, ViewHolderFactory>,
            binderMap: Map<Int, ViewHolderBinder>,
            androidPreconditions: AndroidPreconditions
        ): RecyclerViewAdapter {
            return RecyclerViewAdapter(
                itemComperator = itemComparator,
                viewHolderFactoryMap = factoryMap,
                viewBinderFactoryMap = binderMap,
                androidPreconditions = androidPreconditions
            )
        }
    }

    @Binds
    @IntoMap
    @IntKey(MESSAGES)
    internal abstract fun provideMessagesViewModelFactory(factory: MessagesViewHolder.MessageViewHolderFactory): ViewHolderFactory

    @Binds
    @IntoMap
    @IntKey(MESSAGES)
    internal abstract fun provideMessagesViewHolderBinder(binder: MessagesViewHolder.MessagesViewHolderBinder): ViewHolderBinder
}
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