如果结果有小数,我如何打印出浮点数;如果结果没有小数,我如何打印出整数?
c = input("Enter the total cost of purchase: ")
bank = raw_input("Enter the bank of your credit card (DBS, OCBC, etc.): ")
dbs1 = ((c/float(100))*10)
dbs2 = c-dbs1
ocbc1 = ((c/float(100))*15)
ocbc2 = c-ocbc1
if (c > 200):
if (bank == 'DBS'):
print('Please pay $'+str(dbs2))
elif (bank == 'OCBC'):
print('Please pay $'+str(ocbc2))
else:
print('Please pay $'+str(c))
else:
print('Please pay $'+str(c))
exit = raw_input("Enter to exit")
Enter the total cost of purchase: 250
Enter the bank of your credit card (DBS, OCBC, etc.): OCBC
Please pay $212.5
Enter the total cost of purchase: 250
Enter the bank of your credit card (DBS, OCBC, etc.): DBS
Please pay $225.0
你可以试试这个,它简单地使用了Python的字符串格式化方法:
if int(c) == float(c):
decimals = 0
else:
decimals = 2 # Assumes 2 decimal places for money
print('Please pay: ${0:.{1}f}'.format(c, decimals))
这将为您提供以下输出如果
c == 1.00
:
Please pay: $1
或者这个输出如果
c == 20.56
:
Please pay: $20.56
Python 浮点数有一个内置方法来确定它们是否是整数:
x = 212.50
y = 212.0
f = lambda x: int(x) if x.is_integer() else x
print(x, f(x), y, f(y), sep='\t')
>> 212.5 212.5 212.0 212
既然现在有更简单的方法,这篇文章是第一个结果,人们应该知道它:
print(f"{3.0:g}") # 3
print(f"{3.14:g}") # 3.14
def nice_print(i):
print '%.2f' % i if i - int(i) != 0 else '%d' % i
nice_print(44)
44
nice_print(44.345)
44.34
在你的代码中:
def nice_number(i):
return '%.2f' % i if i - int(i) != 0 else '%d' % i
c = input("Enter the total cost of purchase: ")
bank = raw_input("Enter the bank of your credit card (DBS, OCBC, etc.): ")
dbs1 = ((c/float(100))*10)
dbs2 = c-dbs1
ocbc1 = ((c/float(100))*15)
ocbc2 = c-ocbc1
if (c > 200):
if (bank == 'DBS'):
print('Please pay $'+nice_number(dbs2))
elif (bank == 'OCBC'):
print('Please pay $'+nice_number(ocbc2))
else:
print('Please pay $'+nice_number(c))
else:
print('Please pay $'+nice_number(c))