Tweenlite在多个对象中

问题描述 投票:1回答:1

我试图将卡移动到我的用户他们是三个成员在这里我有九张卡在这里我的代码在下面。我使用tweenlite移动前三张卡成功移动然后其余的卡我怎么能移动到用户。

import com.greensock.*;
import com.greensock.easing.*;
import flash.events.MouseEvent;

 click_mc.addEventListener(MouseEvent.CLICK, UserOne);



function UserOne(evt:MouseEvent):void
{

    TweenMax.to(joker_mc, .5, { x:598.25, y:164.45 , onComplete:UserTwo} );     
}

function UserTwo():void
{
    TweenLite.to(king_mc, .5, { x:316.50, y:267.90, onComplete:UserThree} );

}

function UserThree():void
{
    TweenLite.to(queen_mc, .5, { x:39, y:172} );

}

有人知道请详细说明这个。

actionscript-3 flash actionscript air
1个回答
2
投票

没有必要为每张卡创建单独的代码,它们都是相似的。创建一个带有card + x + y条目的数组,并使用这些条目。

import com.greensock.*;
import com.greensock.easing.*;
import flash.events.MouseEvent;

var currentEntry:int = -1;
var aList:Array =
[
    {card:joker_mc, x:598.25, y:164.45},
    {card:king_mc,  x:316.50, y:267.90},
    {card:queen_mc, x:39, y:172},

    // ...
    // and so on
];

click_mc.addEventListener(MouseEvent.CLICK, onClick);

function onClick(e:MouseEvent):void
{
    // Unsubscribe to avoid the mess with second click.
    click_mc.removeEventListener(MouseEvent.CLICK, onClick);

    // Start process.
    moveNext();
}

function moveNext():void
{
    currentEntry++;

    // Stop the process if all the cards have been moved.
    if (currentEntry >= aList.length) return;

    // Get the entry.
    var anEntry:Object = aList[currentEntry];

    // Move the card.
    TweenLite.to(anEntry['card'], .5, {x:anEntry['x'], y:anEntry['y'], onComplete:moveNext});
}
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