我正在Django中成功检索特定对象的所有记录。
我的url.py是path('city/', views.TestListCity.as_view())
我从邮递员那里得到:http://192.168.99.100:8080/collection/city,它返回所有记录。例如:
{
"id": 3,
"name": "Bor",
"region": {
"id": 2,
"name": "Sun"
}
},
现在我要过滤列为[[name。]的记录>我尝试过:
urls.py
path('city/(?P<name>.+)/$', views.TestListCity.as_view()),
views.py
class TestListCity(generics.RetrieveAPIView):
serializer_class = TestListCitySerializer
def get_queryset(self):
name = self.kwargs['name']
return City.objects.filter(name=name)
我尝试GET:
http://192.168.99.100:8080/collection/city?name=Bor
但随后是404:
<title>Page not found at /collection/city</title>
我也尝试了第二种方法:
urls.py
path('city/<str:name>/', views.TestListCity.as_view())
views.py
class TestListCity(generics.RetrieveAPIView):
serializer_class = TestListCitySerializer
queryset = City.objects.all()
lookup_field = 'name'
但响应完全相同。
我正在Django中成功检索特定对象的所有记录。我的url.py是path('city /',views.TestListCity.as_view())从邮递员那里,我只是得到:http://192.168.99.100:8080/collection/city和...