尝试应用我所学的构建sanke游戏python的方法,但是它不起作用

问题描述 投票:0回答:1

我一直在尝试应用这段视频后到目前为止所学到的知识,但是似乎没有用,为什么?

这是视频的链接。https://www.youtube.com/watch?v=rbasThWVb-c&t=8s

这是我编写的用于运行它的代码。

import random
import curses





s = curses.initscr()
curses.curs_set(0)
sh, sw = s.getmaxyx()
w = curses.newwin(sh,sw, 0,0)
w.keypad(1)
w.timeout(100)

snk_x = sw/4
snk_y =sh/2

snake = [
    [snk_y, snk_x],
    [snk_y,snk_x-1],
    [snk_y,snk_x-2]
]

food = [sh/2,sw/2]

w.addch(food[0], food[1], curses.ACS_PI)

key = curses.KEY_RIGHT


while True:
    next_key = w.getch()
    key = key if next_key == -1 else next_key

    if snake[0][0] in [0,sh] or snake[0][1] in [0,sw] or snake[0] in snake[1:]:
        curses.endwin()
        quit()

    new_head = [snake[0][0], snake[0][1]]


    if key == curses.KEY_DOWN:
        new_head[0]+=1
    if key == curses.KEY_UP:
        new_head[0]-=1
    if key == curses.KEY_LEFT:
        new_head[1]-=1
    if key == curses.KEY_RIGHT:
        new_head[1]+=1

    snake.insert(0, new_head)

    if snake[0] == food:
        food = None
        while food is None
            nf = [
                random.randint(1,sh-1)
                random.randint(1,sw-1)
            ]

            food = nf if nf not in snake else None
        w.addch(food[0],food[1], curses.ACS_PI)
     else:
         tail = snake.pop()
         w.addch(tail[0],tail[1,],' ')
     w.addch(snake[0][0],snake[0][1], curses.ACS_CKBOARD)

顺便说一下,我正在Mac OS上使用TextMate 3编辑器,并试图在IDLE上运行它,如下图所示。enter image description here

python python-3.x python-idle textmate curses
1个回答
1
投票

您的某行缺少冒号:。您还缺少,列表变量之间的逗号nf

   if snake[0] == food:
        food = None
        while food is None:
#Here                     ^
            nf = [
                random.randint(1,sh-1),
#                                     ^
                random.randint(1,sw-1),
#                                     ^
            ]

此外,最后一个else:块未正确缩进您在所有行上都有多余的空间。

else:
        tail = snake.pop()
        w.addch(tail[0],tail[1,],' ')
    w.addch(snake[0][0],snake[0][1], curses.ACS_CKBOARD)

缩进(空格/制表符)在python中很重要,因此Python解释器可以理解您的代码块并正确执行]

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