ORACLE SQL 对列求和并在列表底部显示总计

Question

我用它来创建每个成本值的总计：

SELECT
    ITEM_NO
    COST_1,    
    COST_2,
    COST_3,
    COST_4,   
    SUM(COST_1)  over (order by loan_no rows unbounded preceding ) COST_1_TOTAL,
    SUM(COST_2)  over (order by loan_no rows unbounded preceding ) COST_2_TOTAL,
    SUM(COST_3)  over (order by loan_no rows unbounded preceding ) COST_3_TOTAL,
    SUM(COST_4)  over (order by loan_no rows unbounded preceding ) COST_4_TOTAL
FROM data

它创造了这个：

我希望它看起来像这样：

这可能吗？我不知道从哪里开始......

一如既往，任何建议将不胜感激。

Answer 1

使用

GROUP BY

和

ROLLUP

:

SELECT ITEM_NO,
       SUM(COST_1) AS cost_1,
       SUM(COST_2) AS cost_2,
       SUM(COST_3) AS cost_3,
       SUM(COST_4) AS cost_4
FROM   data
GROUP BY ROLLUP(item_no)

对于样本数据：

CREATE TABLE data (item_no, cost_1, cost_2, cost_3, cost_4) AS
SELECT 1057, 8111.73, -8600, 1550, CAST(NULL AS NUMBER(8,2)) FROM DUAL UNION ALL
SELECT 1693, 7856.25, -8600, 1575, NULL FROM DUAL UNION ALL
SELECT 1701, 5206.20, -8600, 2000, NULL FROM DUAL UNION ALL
SELECT 1784, 6002.97, -8600, 1900, NULL FROM DUAL;

哪个输出：

ITEM_NO	COST_1	COST_2	COST_3	COST_4
1057	8111.73	-8600	1550	空
1693	7856.25	-8600	1575	空
1701	5206.2	-8600	2000	空
1784	6002.97	-8600	1900	空
空	27177.15	-34400	7025	空

小提琴