以编程方式导入Wifi代理设置PAC文件

Question

我正在尝试从URL导入PAC文件并以编程方式更改Wifi代理设置。我搜索后发现可以：

ProxyInfo.buildPacProxy(Uri.parse("someurl")

在问这个问题之前，我检查了here以及所有this。我面临的问题是，当我实现其中一些解决方案时，所有程序都可以正常编译，没有例外，但是当我检查时，没有更新代理设置。这是我最后的代码，但再次失败：

public void setWifiProxySettings5()
{
    //get the current wifi configuration
    WifiManager manager = (WifiManager)getApplicationContext().getSystemService(Context.WIFI_SERVICE);
    WifiConfiguration config = GetCurrentWifiConfiguration(manager);
    if(null == config)
        return;

    try
    {
        //linkProperties is no longer in WifiConfiguration
        Class proxyInfoClass = Class.forName("android.net.ProxyInfo");
        Class[] setHttpProxyParams = new Class[1];
        setHttpProxyParams[0] = proxyInfoClass;
        Class wifiConfigClass = Class.forName("android.net.wifi.WifiConfiguration");
        Method setHttpProxy = wifiConfigClass.getDeclaredMethod("setHttpProxy", setHttpProxyParams);
        setHttpProxy.setAccessible(true);

        Class proxySettingsClass = Class.forName("android.net.IpConfiguration$ProxySettings");

        Class[] setProxySettingsParams = new Class[1];
        setProxySettingsParams[0] = proxySettingsClass;
        Method setProxySettings = wifiConfigClass.getDeclaredMethod("setProxySettings", setProxySettingsParams);
        setProxySettings.setAccessible(true);


        ProxyInfo pacInfo = ProxyInfo.buildPacProxy(Uri.parse("http://localhost/pac"));

        //pass the new object to setHttpProxy
        Object[] params_SetHttpProxy = new Object[1];
        params_SetHttpProxy[0] = pacInfo;
        setHttpProxy.invoke(config, params_SetHttpProxy);

        //pass the enum to setProxySettings
        Object[] params_setProxySettings = new Object[1];
        params_setProxySettings[0] = Enum.valueOf((Class<Enum>) proxySettingsClass, "STATIC");
        setProxySettings.invoke(config, params_setProxySettings);

        //save the settings
        manager.updateNetwork(config);
        manager.disconnect();
        manager.reconnect();
    }
    catch(Exception e)
    {
        Log.v("wifiProxy", e.toString());
    }
}

Answer 1

您是否解决了问题？我有同样的问题。